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Math Problems
Algebra 1
Multiplication with rational exponents
For the function
f
(
x
)
=
−
3
1
+
3
x
f(x)=\frac{-3}{1+3 x}
f
(
x
)
=
1
+
3
x
−
3
, find
f
−
1
(
x
)
f^{-1}(x)
f
−
1
(
x
)
.
\newline
Answer:
f
−
1
(
x
)
=
f^{-1}(x)=
f
−
1
(
x
)
=
Get tutor help
For the function
f
(
x
)
=
3
x
5
x
−
3
f(x)=\frac{3 x}{5 x-3}
f
(
x
)
=
5
x
−
3
3
x
, find
f
−
1
(
x
)
f^{-1}(x)
f
−
1
(
x
)
.
\newline
Answer:
f
−
1
(
x
)
=
f^{-1}(x)=
f
−
1
(
x
)
=
Get tutor help
For the function
f
(
x
)
=
3
x
1
3
f(x)=3 x^{\frac{1}{3}}
f
(
x
)
=
3
x
3
1
, find
f
−
1
(
x
)
f^{-1}(x)
f
−
1
(
x
)
.
\newline
f
−
1
(
x
)
=
3
x
3
f^{-1}(x)=3 x^{3}
f
−
1
(
x
)
=
3
x
3
\newline
f
−
1
(
x
)
=
(
x
3
)
1
3
f^{-1}(x)=\left(\frac{x}{3}\right)^{\frac{1}{3}}
f
−
1
(
x
)
=
(
3
x
)
3
1
\newline
f
−
1
(
x
)
=
x
3
3
f^{-1}(x)=\frac{x^{3}}{3}
f
−
1
(
x
)
=
3
x
3
\newline
f
−
1
(
x
)
=
(
x
3
)
3
f^{-1}(x)=\left(\frac{x}{3}\right)^{3}
f
−
1
(
x
)
=
(
3
x
)
3
Get tutor help
For the function
f
(
x
)
=
(
x
5
)
1
3
f(x)=\left(\frac{x}{5}\right)^{\frac{1}{3}}
f
(
x
)
=
(
5
x
)
3
1
, find
f
−
1
(
x
)
f^{-1}(x)
f
−
1
(
x
)
.
\newline
f
−
1
(
x
)
=
(
5
x
)
3
f^{-1}(x)=(5 x)^{3}
f
−
1
(
x
)
=
(
5
x
)
3
\newline
f
−
1
(
x
)
=
5
x
3
f^{-1}(x)=5 x^{3}
f
−
1
(
x
)
=
5
x
3
\newline
f
−
1
(
x
)
=
(
x
5
)
3
f^{-1}(x)=\left(\frac{x}{5}\right)^{3}
f
−
1
(
x
)
=
(
5
x
)
3
\newline
f
−
1
(
x
)
=
(
5
x
)
1
3
f^{-1}(x)=(5 x)^{\frac{1}{3}}
f
−
1
(
x
)
=
(
5
x
)
3
1
Get tutor help
For the function
f
(
x
)
=
7
x
1
3
f(x)=7 x^{\frac{1}{3}}
f
(
x
)
=
7
x
3
1
, find
f
−
1
(
x
)
f^{-1}(x)
f
−
1
(
x
)
.
\newline
f
−
1
(
x
)
=
(
x
7
)
3
f^{-1}(x)=\left(\frac{x}{7}\right)^{3}
f
−
1
(
x
)
=
(
7
x
)
3
\newline
f
−
1
(
x
)
=
x
3
7
f^{-1}(x)=\frac{x^{3}}{7}
f
−
1
(
x
)
=
7
x
3
\newline
f
−
1
(
x
)
=
(
7
x
)
3
f^{-1}(x)=(7 x)^{3}
f
−
1
(
x
)
=
(
7
x
)
3
\newline
f
−
1
(
x
)
=
7
x
3
f^{-1}(x)=7 x^{3}
f
−
1
(
x
)
=
7
x
3
Get tutor help
For the function
f
(
x
)
=
x
5
+
1
5
f(x)=\frac{\sqrt[5]{x}+1}{5}
f
(
x
)
=
5
5
x
+
1
, find
f
−
1
(
x
)
f^{-1}(x)
f
−
1
(
x
)
.
\newline
f
−
1
(
x
)
=
5
(
x
5
−
1
)
f^{-1}(x)=5\left(x^{5}-1\right)
f
−
1
(
x
)
=
5
(
x
5
−
1
)
\newline
f
−
1
(
x
)
=
5
(
x
−
1
)
5
f^{-1}(x)=5(x-1)^{5}
f
−
1
(
x
)
=
5
(
x
−
1
)
5
\newline
f
−
1
(
x
)
=
(
5
x
−
1
)
5
f^{-1}(x)=(5 x-1)^{5}
f
−
1
(
x
)
=
(
5
x
−
1
)
5
\newline
f
−
1
(
x
)
=
(
5
x
)
5
−
1
f^{-1}(x)=(5 x)^{5}-1
f
−
1
(
x
)
=
(
5
x
)
5
−
1
Get tutor help
For the function
f
(
x
)
=
3
(
x
3
−
10
)
f(x)=3(\sqrt[3]{x}-10)
f
(
x
)
=
3
(
3
x
−
10
)
, find
f
−
1
(
x
)
f^{-1}(x)
f
−
1
(
x
)
.
\newline
f
−
1
(
x
)
=
(
x
3
)
3
+
10
f^{-1}(x)=\left(\frac{x}{3}\right)^{3}+10
f
−
1
(
x
)
=
(
3
x
)
3
+
10
\newline
f
−
1
(
x
)
=
(
x
3
+
10
)
3
f^{-1}(x)=\left(\frac{x}{3}+10\right)^{3}
f
−
1
(
x
)
=
(
3
x
+
10
)
3
\newline
f
−
1
(
x
)
=
x
3
3
+
10
f^{-1}(x)=\frac{x^{3}}{3}+10
f
−
1
(
x
)
=
3
x
3
+
10
\newline
f
−
1
(
x
)
=
x
3
+
10
3
f^{-1}(x)=\frac{x^{3}+10}{3}
f
−
1
(
x
)
=
3
x
3
+
10
Get tutor help
For the function
f
(
x
)
=
(
x
+
5
)
1
5
f(x)=(x+5)^{\frac{1}{5}}
f
(
x
)
=
(
x
+
5
)
5
1
, find
f
−
1
(
x
)
f^{-1}(x)
f
−
1
(
x
)
.
\newline
f
−
1
(
x
)
=
(
x
+
5
)
5
f^{-1}(x)=(x+5)^{5}
f
−
1
(
x
)
=
(
x
+
5
)
5
\newline
f
−
1
(
x
)
=
x
1
5
−
5
f^{-1}(x)=x^{\frac{1}{5}}-5
f
−
1
(
x
)
=
x
5
1
−
5
\newline
f
−
1
(
x
)
=
x
5
−
5
f^{-1}(x)=x^{5}-5
f
−
1
(
x
)
=
x
5
−
5
\newline
f
−
1
(
x
)
=
(
x
−
5
)
1
5
f^{-1}(x)=(x-5)^{\frac{1}{5}}
f
−
1
(
x
)
=
(
x
−
5
)
5
1
Get tutor help
For the function
f
(
x
)
=
7
x
5
f(x)=7 x^{5}
f
(
x
)
=
7
x
5
, find
f
−
1
(
x
)
f^{-1}(x)
f
−
1
(
x
)
.
\newline
f
−
1
(
x
)
=
7
x
5
f^{-1}(x)=7 \sqrt[5]{x}
f
−
1
(
x
)
=
7
5
x
\newline
f
−
1
(
x
)
=
(
x
7
)
5
f^{-1}(x)=\sqrt[5]{\left(\frac{x}{7}\right)}
f
−
1
(
x
)
=
5
(
7
x
)
\newline
f
−
1
(
x
)
=
(
x
7
)
5
f^{-1}(x)=\left(\frac{x}{7}\right)^{5}
f
−
1
(
x
)
=
(
7
x
)
5
\newline
f
−
1
(
x
)
=
x
5
7
f^{-1}(x)=\frac{\sqrt[5]{x}}{7}
f
−
1
(
x
)
=
7
5
x
Get tutor help
For the function
f
(
x
)
=
x
1
3
4
f(x)=\frac{x^{\frac{1}{3}}}{4}
f
(
x
)
=
4
x
3
1
, find
f
−
1
(
x
)
f^{-1}(x)
f
−
1
(
x
)
.
\newline
f
−
1
(
x
)
=
4
x
1
3
f^{-1}(x)=4 x^{\frac{1}{3}}
f
−
1
(
x
)
=
4
x
3
1
\newline
f
−
1
(
x
)
=
4
x
3
f^{-1}(x)=4 x^{3}
f
−
1
(
x
)
=
4
x
3
\newline
f
−
1
(
x
)
=
(
4
x
)
3
f^{-1}(x)=(4 x)^{3}
f
−
1
(
x
)
=
(
4
x
)
3
\newline
f
−
1
(
x
)
=
(
x
4
)
3
f^{-1}(x)=\left(\frac{x}{4}\right)^{3}
f
−
1
(
x
)
=
(
4
x
)
3
Get tutor help
For the function
f
(
x
)
=
(
x
7
)
7
f(x)=\sqrt[7]{\left(\frac{x}{7}\right)}
f
(
x
)
=
7
(
7
x
)
, find
f
−
1
(
x
)
f^{-1}(x)
f
−
1
(
x
)
.
\newline
f
−
1
(
x
)
=
7
x
7
f^{-1}(x)=7 x^{7}
f
−
1
(
x
)
=
7
x
7
\newline
f
−
1
(
x
)
=
x
7
7
f^{-1}(x)=\frac{x^{7}}{7}
f
−
1
(
x
)
=
7
x
7
\newline
f
−
1
(
x
)
=
(
7
x
)
7
f^{-1}(x)=\sqrt[7]{(7 x)}
f
−
1
(
x
)
=
7
(
7
x
)
\newline
f
−
1
(
x
)
=
(
7
x
)
7
f^{-1}(x)=(7 x)^{7}
f
−
1
(
x
)
=
(
7
x
)
7
Get tutor help
For the function
f
(
x
)
=
(
x
7
)
7
f(x)=\left(\frac{x}{7}\right)^{7}
f
(
x
)
=
(
7
x
)
7
, find
f
−
1
(
x
)
f^{-1}(x)
f
−
1
(
x
)
.
\newline
f
−
1
(
x
)
=
(
7
x
)
7
f^{-1}(x)=\sqrt[7]{(7 x)}
f
−
1
(
x
)
=
7
(
7
x
)
\newline
f
−
1
(
x
)
=
(
x
7
)
7
f^{-1}(x)=\sqrt[7]{\left(\frac{x}{7}\right)}
f
−
1
(
x
)
=
7
(
7
x
)
\newline
f
−
1
(
x
)
=
7
x
7
f^{-1}(x)=7 \sqrt[7]{x}
f
−
1
(
x
)
=
7
7
x
\newline
f
−
1
(
x
)
=
x
7
7
f^{-1}(x)=\frac{\sqrt[7]{x}}{7}
f
−
1
(
x
)
=
7
7
x
Get tutor help
For the function
f
(
x
)
=
4
x
1
5
f(x)=4 x^{\frac{1}{5}}
f
(
x
)
=
4
x
5
1
, find
f
−
1
(
x
)
f^{-1}(x)
f
−
1
(
x
)
.
\newline
f
−
1
(
x
)
=
(
x
4
)
5
f^{-1}(x)=\left(\frac{x}{4}\right)^{5}
f
−
1
(
x
)
=
(
4
x
)
5
\newline
f
−
1
(
x
)
=
x
5
4
f^{-1}(x)=\frac{x^{5}}{4}
f
−
1
(
x
)
=
4
x
5
\newline
f
−
1
(
x
)
=
x
1
5
4
f^{-1}(x)=\frac{x^{\frac{1}{5}}}{4}
f
−
1
(
x
)
=
4
x
5
1
\newline
f
−
1
(
x
)
=
(
4
x
)
5
f^{-1}(x)=(4 x)^{5}
f
−
1
(
x
)
=
(
4
x
)
5
Get tutor help
For the function
f
(
x
)
=
(
x
−
4
)
3
f(x)=\frac{(x-4)}{3}
f
(
x
)
=
3
(
x
−
4
)
, find
f
−
1
(
x
)
f^{-1}(x)
f
−
1
(
x
)
.
\newline
f
−
1
(
x
)
=
(
x
+
4
)
3
f^{-1}(x)=\frac{(x+4)}{3}
f
−
1
(
x
)
=
3
(
x
+
4
)
\newline
f
−
1
(
x
)
=
3
(
x
−
4
)
f^{-1}(x)=3(x-4)
f
−
1
(
x
)
=
3
(
x
−
4
)
\newline
f
−
1
(
x
)
=
3
(
x
+
4
)
f^{-1}(x)=3(x+4)
f
−
1
(
x
)
=
3
(
x
+
4
)
\newline
f
−
1
(
x
)
=
3
x
+
4
f^{-1}(x)=3 x+4
f
−
1
(
x
)
=
3
x
+
4
Get tutor help
For the function
f
(
x
)
=
x
1
3
7
f(x)=\frac{x^{\frac{1}{3}}}{7}
f
(
x
)
=
7
x
3
1
, find
f
−
1
(
x
)
f^{-1}(x)
f
−
1
(
x
)
.
\newline
f
−
1
(
x
)
=
7
x
1
3
f^{-1}(x)=7 x^{\frac{1}{3}}
f
−
1
(
x
)
=
7
x
3
1
\newline
f
−
1
(
x
)
=
(
7
x
)
3
f^{-1}(x)=(7 x)^{3}
f
−
1
(
x
)
=
(
7
x
)
3
\newline
f
−
1
(
x
)
=
(
7
x
)
1
3
f^{-1}(x)=(7 x)^{\frac{1}{3}}
f
−
1
(
x
)
=
(
7
x
)
3
1
\newline
f
−
1
(
x
)
=
x
3
7
f^{-1}(x)=\frac{x^{3}}{7}
f
−
1
(
x
)
=
7
x
3
Get tutor help
For the function
f
(
x
)
=
7
x
1
5
f(x)=7 x^{\frac{1}{5}}
f
(
x
)
=
7
x
5
1
, find
f
−
1
(
x
)
f^{-1}(x)
f
−
1
(
x
)
.
\newline
f
−
1
(
x
)
=
(
7
x
)
5
f^{-1}(x)=(7 x)^{5}
f
−
1
(
x
)
=
(
7
x
)
5
\newline
f
−
1
(
x
)
=
x
5
7
f^{-1}(x)=\frac{x^{5}}{7}
f
−
1
(
x
)
=
7
x
5
\newline
f
−
1
(
x
)
=
(
x
7
)
5
f^{-1}(x)=\left(\frac{x}{7}\right)^{5}
f
−
1
(
x
)
=
(
7
x
)
5
\newline
f
−
1
(
x
)
=
x
1
5
7
f^{-1}(x)=\frac{x^{\frac{1}{5}}}{7}
f
−
1
(
x
)
=
7
x
5
1
Get tutor help
Find the inverse function of the function
f
(
x
)
=
5
x
5
f(x)=\sqrt[5]{5 x}
f
(
x
)
=
5
5
x
.
\newline
f
−
1
(
x
)
=
x
5
3125
f^{-1}(x)=\frac{x^{5}}{3125}
f
−
1
(
x
)
=
3125
x
5
\newline
f
−
1
(
x
)
=
x
5
5
f^{-1}(x)=\frac{x^{5}}{5}
f
−
1
(
x
)
=
5
x
5
\newline
f
−
1
(
x
)
=
5
x
5
f^{-1}(x)=5 x^{5}
f
−
1
(
x
)
=
5
x
5
\newline
f
−
1
(
x
)
=
3125
x
5
f^{-1}(x)=3125 x^{5}
f
−
1
(
x
)
=
3125
x
5
Get tutor help
Find the inverse function of the function
f
(
x
)
=
4
x
−
7
3
f(x)=4 x^{-\frac{7}{3}}
f
(
x
)
=
4
x
−
3
7
on the domain
x
>
0
x>0
x
>
0
.
\newline
f
−
1
(
x
)
=
(
x
4
)
−
3
7
f^{-1}(x)=\left(\frac{x}{4}\right)^{-\frac{3}{7}}
f
−
1
(
x
)
=
(
4
x
)
−
7
3
\newline
f
−
1
(
x
)
=
x
−
3
7
4
f^{-1}(x)=\frac{x^{-\frac{3}{7}}}{4}
f
−
1
(
x
)
=
4
x
−
7
3
\newline
f
−
1
(
x
)
=
(
x
4
)
−
7
3
f^{-1}(x)=\left(\frac{x}{4}\right)^{-\frac{7}{3}}
f
−
1
(
x
)
=
(
4
x
)
−
3
7
\newline
f
−
1
(
x
)
=
x
−
7
3
4
f^{-1}(x)=\frac{x^{-\frac{7}{3}}}{4}
f
−
1
(
x
)
=
4
x
−
3
7
Get tutor help
Find the inverse function of the function
f
(
x
)
=
5
x
3
f(x)=\sqrt[3]{5 x}
f
(
x
)
=
3
5
x
.
\newline
f
−
1
(
x
)
=
x
2
25
f^{-1}(x)=\frac{x^{2}}{25}
f
−
1
(
x
)
=
25
x
2
\newline
f
−
1
(
x
)
=
x
3
125
f^{-1}(x)=\frac{x^{3}}{125}
f
−
1
(
x
)
=
125
x
3
\newline
f
−
1
(
x
)
=
x
3
5
f^{-1}(x)=\frac{x^{3}}{5}
f
−
1
(
x
)
=
5
x
3
\newline
f
−
1
(
x
)
=
x
2
5
f^{-1}(x)=\frac{x^{2}}{5}
f
−
1
(
x
)
=
5
x
2
Get tutor help
Find the inverse function of the function
f
(
x
)
=
4
x
9
7
f(x)=4 x^{\frac{9}{7}}
f
(
x
)
=
4
x
7
9
on the domain
x
≥
0
x \geq 0
x
≥
0
.
\newline
f
−
1
(
x
)
=
(
x
4
)
−
7
9
f^{-1}(x)=\left(\frac{x}{4}\right)^{-\frac{7}{9}}
f
−
1
(
x
)
=
(
4
x
)
−
9
7
\newline
f
−
1
(
x
)
=
(
x
4
)
7
9
f^{-1}(x)=\left(\frac{x}{4}\right)^{\frac{7}{9}}
f
−
1
(
x
)
=
(
4
x
)
9
7
\newline
f
−
1
(
x
)
=
x
−
7
9
4
f^{-1}(x)=\frac{x^{-\frac{7}{9}}}{4}
f
−
1
(
x
)
=
4
x
−
9
7
\newline
f
−
1
(
x
)
=
x
7
9
4
f^{-1}(x)=\frac{x^{\frac{7}{9}}}{4}
f
−
1
(
x
)
=
4
x
9
7
Get tutor help
Find the inverse function of the function
f
(
x
)
=
(
5
x
)
5
9
f(x)=(5 x)^{\frac{5}{9}}
f
(
x
)
=
(
5
x
)
9
5
on the domain
x
≥
0
x \geq 0
x
≥
0
.
\newline
f
−
1
(
x
)
=
(
x
5
)
−
9
5
f^{-1}(x)=\left(\frac{x}{5}\right)^{-\frac{9}{5}}
f
−
1
(
x
)
=
(
5
x
)
−
5
9
\newline
f
−
1
(
x
)
=
(
x
5
)
9
5
f^{-1}(x)=\left(\frac{x}{5}\right)^{\frac{9}{5}}
f
−
1
(
x
)
=
(
5
x
)
5
9
\newline
f
−
1
(
x
)
=
x
9
5
5
f^{-1}(x)=\frac{x^{\frac{9}{5}}}{5}
f
−
1
(
x
)
=
5
x
5
9
\newline
f
−
1
(
x
)
=
x
−
9
5
5
f^{-1}(x)=\frac{x^{-\frac{9}{5}}}{5}
f
−
1
(
x
)
=
5
x
−
5
9
Get tutor help
Find the inverse function of the function
f
(
x
)
=
4
x
5
f(x)=4 \sqrt[5]{x}
f
(
x
)
=
4
5
x
.
\newline
f
−
1
(
x
)
=
x
5
1024
f^{-1}(x)=\frac{x^{5}}{1024}
f
−
1
(
x
)
=
1024
x
5
\newline
f
−
1
(
x
)
=
x
5
4
f^{-1}(x)=\frac{x^{5}}{4}
f
−
1
(
x
)
=
4
x
5
\newline
f
−
1
(
x
)
=
4
x
5
f^{-1}(x)=4 x^{5}
f
−
1
(
x
)
=
4
x
5
\newline
f
−
1
(
x
)
=
1024
x
5
f^{-1}(x)=1024 x^{5}
f
−
1
(
x
)
=
1024
x
5
Get tutor help
Find the inverse function of the function
f
(
x
)
=
(
5
x
)
−
9
5
f(x)=(5 x)^{-\frac{9}{5}}
f
(
x
)
=
(
5
x
)
−
5
9
on the domain
x
>
0
x>0
x
>
0
.
\newline
f
−
1
(
x
)
=
(
x
5
)
5
9
f^{-1}(x)=\left(\frac{x}{5}\right)^{\frac{5}{9}}
f
−
1
(
x
)
=
(
5
x
)
9
5
\newline
f
−
1
(
x
)
=
x
−
5
9
5
f^{-1}(x)=\frac{x^{-\frac{5}{9}}}{5}
f
−
1
(
x
)
=
5
x
−
9
5
\newline
f
−
1
(
x
)
=
(
x
5
)
−
5
9
f^{-1}(x)=\left(\frac{x}{5}\right)^{-\frac{5}{9}}
f
−
1
(
x
)
=
(
5
x
)
−
9
5
\newline
f
−
1
(
x
)
=
x
5
9
5
f^{-1}(x)=\frac{x^{\frac{5}{9}}}{5}
f
−
1
(
x
)
=
5
x
9
5
Get tutor help
Find the inverse function of the function
f
(
x
)
=
(
4
x
)
9
5
f(x)=(4 x)^{\frac{9}{5}}
f
(
x
)
=
(
4
x
)
5
9
on the domain
x
≥
0
x \geq 0
x
≥
0
.
\newline
f
−
1
(
x
)
=
x
5
9
4
f^{-1}(x)=\frac{x^{\frac{5}{9}}}{4}
f
−
1
(
x
)
=
4
x
9
5
\newline
f
−
1
(
x
)
=
(
x
4
)
5
9
f^{-1}(x)=\left(\frac{x}{4}\right)^{\frac{5}{9}}
f
−
1
(
x
)
=
(
4
x
)
9
5
\newline
f
−
1
(
x
)
=
x
9
5
4
f^{-1}(x)=\frac{x^{\frac{9}{5}}}{4}
f
−
1
(
x
)
=
4
x
5
9
\newline
f
−
1
(
x
)
=
(
x
4
)
9
5
f^{-1}(x)=\left(\frac{x}{4}\right)^{\frac{9}{5}}
f
−
1
(
x
)
=
(
4
x
)
5
9
Get tutor help
Find the inverse function of the function
f
(
x
)
=
−
8
x
3
f(x)=-\frac{8 x}{3}
f
(
x
)
=
−
3
8
x
.
\newline
f
−
1
(
x
)
=
3
8
x
f^{-1}(x)=\frac{3}{8 x}
f
−
1
(
x
)
=
8
x
3
\newline
f
−
1
(
x
)
=
3
x
8
f^{-1}(x)=\frac{3 x}{8}
f
−
1
(
x
)
=
8
3
x
\newline
f
−
1
(
x
)
=
−
3
x
8
f^{-1}(x)=-\frac{3 x}{8}
f
−
1
(
x
)
=
−
8
3
x
\newline
f
−
1
(
x
)
=
−
3
8
x
f^{-1}(x)=-\frac{3}{8 x}
f
−
1
(
x
)
=
−
8
x
3
Get tutor help
Find the inverse function of the function
f
(
x
)
=
1
2
x
+
2
f(x)=\frac{1}{2} x+2
f
(
x
)
=
2
1
x
+
2
.
\newline
f
−
1
(
x
)
=
2
x
−
2
f^{-1}(x)=2 x-2
f
−
1
(
x
)
=
2
x
−
2
\newline
f
−
1
(
x
)
=
1
2
x
−
2
f^{-1}(x)=\frac{1}{2} x-2
f
−
1
(
x
)
=
2
1
x
−
2
\newline
f
−
1
(
x
)
=
2
x
−
4
f^{-1}(x)=2 x-4
f
−
1
(
x
)
=
2
x
−
4
\newline
f
−
1
(
x
)
=
1
2
x
−
4
f^{-1}(x)=\frac{1}{2} x-4
f
−
1
(
x
)
=
2
1
x
−
4
Get tutor help
Find the inverse function of the function
f
(
x
)
=
−
8
x
9
f(x)=-\frac{8 x}{9}
f
(
x
)
=
−
9
8
x
.
\newline
f
−
1
(
x
)
=
8
x
9
f^{-1}(x)=\frac{8 x}{9}
f
−
1
(
x
)
=
9
8
x
\newline
f
−
1
(
x
)
=
−
9
x
8
f^{-1}(x)=-\frac{9 x}{8}
f
−
1
(
x
)
=
−
8
9
x
\newline
f
−
1
(
x
)
=
9
x
8
f^{-1}(x)=\frac{9 x}{8}
f
−
1
(
x
)
=
8
9
x
\newline
f
−
1
(
x
)
=
−
8
x
9
f^{-1}(x)=-\frac{8 x}{9}
f
−
1
(
x
)
=
−
9
8
x
Get tutor help
Find the inverse function of the function
f
(
x
)
=
2
x
9
7
f(x)=2 x^{\frac{9}{7}}
f
(
x
)
=
2
x
7
9
on the domain
x
≥
0
x \geq 0
x
≥
0
.
\newline
f
−
1
(
x
)
=
(
x
2
)
7
9
f^{-1}(x)=\left(\frac{x}{2}\right)^{\frac{7}{9}}
f
−
1
(
x
)
=
(
2
x
)
9
7
\newline
f
−
1
(
x
)
=
(
x
2
)
−
7
9
f^{-1}(x)=\left(\frac{x}{2}\right)^{-\frac{7}{9}}
f
−
1
(
x
)
=
(
2
x
)
−
9
7
\newline
f
−
1
(
x
)
=
x
−
7
9
2
f^{-1}(x)=\frac{x^{-\frac{7}{9}}}{2}
f
−
1
(
x
)
=
2
x
−
9
7
\newline
f
−
1
(
x
)
=
x
7
9
2
f^{-1}(x)=\frac{x^{\frac{7}{9}}}{2}
f
−
1
(
x
)
=
2
x
9
7
Get tutor help
Find the inverse function of the function
f
(
x
)
=
2
9
x
f(x)=\frac{2}{9 x}
f
(
x
)
=
9
x
2
.
\newline
f
−
1
(
x
)
=
9
2
x
f^{-1}(x)=\frac{9}{2 x}
f
−
1
(
x
)
=
2
x
9
\newline
f
−
1
(
x
)
=
−
2
9
x
f^{-1}(x)=-\frac{2}{9 x}
f
−
1
(
x
)
=
−
9
x
2
\newline
f
−
1
(
x
)
=
2
9
x
f^{-1}(x)=\frac{2}{9 x}
f
−
1
(
x
)
=
9
x
2
\newline
f
−
1
(
x
)
=
−
9
2
x
f^{-1}(x)=-\frac{9}{2 x}
f
−
1
(
x
)
=
−
2
x
9
Get tutor help
Find the inverse function of the function
f
(
x
)
=
5
x
−
7
3
f(x)=5 x^{-\frac{7}{3}}
f
(
x
)
=
5
x
−
3
7
on the domain
x
>
0
x>0
x
>
0
.
\newline
f
−
1
(
x
)
=
x
−
3
7
5
f^{-1}(x)=\frac{x^{-\frac{3}{7}}}{5}
f
−
1
(
x
)
=
5
x
−
7
3
\newline
f
−
1
(
x
)
=
x
−
7
3
5
f^{-1}(x)=\frac{x^{-\frac{7}{3}}}{5}
f
−
1
(
x
)
=
5
x
−
3
7
\newline
f
−
1
(
x
)
=
(
x
5
)
−
7
3
f^{-1}(x)=\left(\frac{x}{5}\right)^{-\frac{7}{3}}
f
−
1
(
x
)
=
(
5
x
)
−
3
7
\newline
f
−
1
(
x
)
=
(
x
5
)
−
3
7
f^{-1}(x)=\left(\frac{x}{5}\right)^{-\frac{3}{7}}
f
−
1
(
x
)
=
(
5
x
)
−
7
3
Get tutor help
Find the inverse function of the function
f
(
x
)
=
2
x
3
5
f(x)=2 x^{\frac{3}{5}}
f
(
x
)
=
2
x
5
3
on the domain
x
≥
0
x \geq 0
x
≥
0
.
\newline
f
−
1
(
x
)
=
(
x
2
)
5
3
f^{-1}(x)=\left(\frac{x}{2}\right)^{\frac{5}{3}}
f
−
1
(
x
)
=
(
2
x
)
3
5
\newline
f
−
1
(
x
)
=
(
x
2
)
−
5
3
f^{-1}(x)=\left(\frac{x}{2}\right)^{-\frac{5}{3}}
f
−
1
(
x
)
=
(
2
x
)
−
3
5
\newline
f
−
1
(
x
)
=
x
−
5
3
2
f^{-1}(x)=\frac{x^{-\frac{5}{3}}}{2}
f
−
1
(
x
)
=
2
x
−
3
5
\newline
f
−
1
(
x
)
=
x
5
3
2
f^{-1}(x)=\frac{x^{\frac{5}{3}}}{2}
f
−
1
(
x
)
=
2
x
3
5
Get tutor help
Find the inverse function of the function
f
(
x
)
=
(
3
x
)
7
5
f(x)=(3 x)^{\frac{7}{5}}
f
(
x
)
=
(
3
x
)
5
7
on the domain
x
≥
0
x \geq 0
x
≥
0
.
\newline
f
−
1
(
x
)
=
3
x
5
7
f^{-1}(x)=3 x^{\frac{5}{7}}
f
−
1
(
x
)
=
3
x
7
5
\newline
f
−
1
(
x
)
=
x
5
7
3
f^{-1}(x)=\frac{x^{\frac{5}{7}}}{3}
f
−
1
(
x
)
=
3
x
7
5
\newline
f
−
1
(
x
)
=
(
x
3
)
5
7
f^{-1}(x)=\left(\frac{x}{3}\right)^{\frac{5}{7}}
f
−
1
(
x
)
=
(
3
x
)
7
5
\newline
f
−
1
(
x
)
=
(
3
x
)
5
7
f^{-1}(x)=(3 x)^{\frac{5}{7}}
f
−
1
(
x
)
=
(
3
x
)
7
5
Get tutor help
Find the inverse function of the function
f
(
x
)
=
2
x
5
f(x)=2 \sqrt[5]{x}
f
(
x
)
=
2
5
x
.
\newline
f
−
1
(
x
)
=
−
x
5
32
f^{-1}(x)=-\frac{x^{5}}{32}
f
−
1
(
x
)
=
−
32
x
5
\newline
f
−
1
(
x
)
=
x
5
32
f^{-1}(x)=\frac{x^{5}}{32}
f
−
1
(
x
)
=
32
x
5
\newline
f
−
1
(
x
)
=
−
x
5
2
f^{-1}(x)=-\frac{x^{5}}{2}
f
−
1
(
x
)
=
−
2
x
5
\newline
f
−
1
(
x
)
=
x
5
2
f^{-1}(x)=\frac{x^{5}}{2}
f
−
1
(
x
)
=
2
x
5
Get tutor help
For the function
f
(
x
)
=
(
x
1
7
5
)
3
f(x)=\left(\frac{x^{\frac{1}{7}}}{5}\right)^{3}
f
(
x
)
=
(
5
x
7
1
)
3
, find
f
−
1
(
x
)
f^{-1}(x)
f
−
1
(
x
)
.
\newline
f
−
1
(
x
)
=
(
5
x
3
)
7
f^{-1}(x)=(\sqrt[3]{5 x})^{7}
f
−
1
(
x
)
=
(
3
5
x
)
7
\newline
f
−
1
(
x
)
=
5
x
7
3
f^{-1}(x)=5 \sqrt[3]{x^{7}}
f
−
1
(
x
)
=
5
3
x
7
\newline
f
−
1
(
x
)
=
5
x
7
3
f^{-1}(x)=\sqrt[3]{5 x^{7}}
f
−
1
(
x
)
=
3
5
x
7
\newline
f
−
1
(
x
)
=
(
5
x
3
)
7
f^{-1}(x)=(5 \sqrt[3]{x})^{7}
f
−
1
(
x
)
=
(
5
3
x
)
7
Get tutor help
For the function
f
(
x
)
=
6
x
7
−
4
f(x)=6 x^{7}-4
f
(
x
)
=
6
x
7
−
4
, find
f
−
1
(
x
)
f^{-1}(x)
f
−
1
(
x
)
.
\newline
f
−
1
(
x
)
=
x
+
4
7
6
f^{-1}(x)=\frac{\sqrt[7]{x+4}}{6}
f
−
1
(
x
)
=
6
7
x
+
4
\newline
f
−
1
(
x
)
=
x
+
4
6
7
f^{-1}(x)=\sqrt[7]{\frac{x+4}{6}}
f
−
1
(
x
)
=
7
6
x
+
4
\newline
f
−
1
(
x
)
=
x
6
7
+
4
f^{-1}(x)=\sqrt[7]{\frac{x}{6}}+4
f
−
1
(
x
)
=
7
6
x
+
4
\newline
f
−
1
(
x
)
=
x
7
6
+
4
f^{-1}(x)=\frac{\sqrt[7]{x}}{6}+4
f
−
1
(
x
)
=
6
7
x
+
4
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For the function
f
(
x
)
=
x
7
+
5
4
f(x)=\frac{\sqrt[7]{x}+5}{4}
f
(
x
)
=
4
7
x
+
5
, find
f
−
1
(
x
)
f^{-1}(x)
f
−
1
(
x
)
.
\newline
f
−
1
(
x
)
=
4
(
x
7
−
5
)
f^{-1}(x)=4\left(x^{7}-5\right)
f
−
1
(
x
)
=
4
(
x
7
−
5
)
\newline
f
−
1
(
x
)
=
4
x
7
−
5
f^{-1}(x)=4 x^{7}-5
f
−
1
(
x
)
=
4
x
7
−
5
\newline
f
−
1
(
x
)
=
(
4
x
−
5
)
7
f^{-1}(x)=(4 x-5)^{7}
f
−
1
(
x
)
=
(
4
x
−
5
)
7
\newline
f
−
1
(
x
)
=
4
(
x
−
5
)
7
f^{-1}(x)=4(x-5)^{7}
f
−
1
(
x
)
=
4
(
x
−
5
)
7
Get tutor help
Find the inverse function of the function
f
(
x
)
=
(
3
x
)
−
5
3
f(x)=(3 x)^{-\frac{5}{3}}
f
(
x
)
=
(
3
x
)
−
3
5
on the domain
x
>
0
x>0
x
>
0
.
\newline
f
−
1
(
x
)
=
(
x
3
)
3
5
f^{-1}(x)=\left(\frac{x}{3}\right)^{\frac{3}{5}}
f
−
1
(
x
)
=
(
3
x
)
5
3
\newline
f
−
1
(
x
)
=
x
3
5
3
f^{-1}(x)=\frac{x^{\frac{3}{5}}}{3}
f
−
1
(
x
)
=
3
x
5
3
\newline
f
−
1
(
x
)
=
(
x
3
)
−
3
5
f^{-1}(x)=\left(\frac{x}{3}\right)^{-\frac{3}{5}}
f
−
1
(
x
)
=
(
3
x
)
−
5
3
\newline
f
−
1
(
x
)
=
x
−
3
5
3
f^{-1}(x)=\frac{x^{-\frac{3}{5}}}{3}
f
−
1
(
x
)
=
3
x
−
5
3
Get tutor help
Find the inverse function of the function
f
(
x
)
=
4
x
5
3
f(x)=4 x^{\frac{5}{3}}
f
(
x
)
=
4
x
3
5
on the domain
x
≥
0
x \geq 0
x
≥
0
.
\newline
f
−
1
(
x
)
=
(
x
4
)
3
5
f^{-1}(x)=\left(\frac{x}{4}\right)^{\frac{3}{5}}
f
−
1
(
x
)
=
(
4
x
)
5
3
\newline
f
−
1
(
x
)
=
x
−
3
5
4
f^{-1}(x)=\frac{x^{-\frac{3}{5}}}{4}
f
−
1
(
x
)
=
4
x
−
5
3
\newline
f
−
1
(
x
)
=
x
3
5
4
f^{-1}(x)=\frac{x^{\frac{3}{5}}}{4}
f
−
1
(
x
)
=
4
x
5
3
\newline
f
−
1
(
x
)
=
(
x
4
)
−
3
5
f^{-1}(x)=\left(\frac{x}{4}\right)^{-\frac{3}{5}}
f
−
1
(
x
)
=
(
4
x
)
−
5
3
Get tutor help
Find the inverse function of the function
f
(
x
)
=
1
2
x
+
4
f(x)=\frac{1}{2} x+4
f
(
x
)
=
2
1
x
+
4
.
\newline
f
−
1
(
x
)
=
1
2
x
−
8
f^{-1}(x)=\frac{1}{2} x-8
f
−
1
(
x
)
=
2
1
x
−
8
\newline
f
−
1
(
x
)
=
1
2
x
−
4
f^{-1}(x)=\frac{1}{2} x-4
f
−
1
(
x
)
=
2
1
x
−
4
\newline
f
−
1
(
x
)
=
2
x
−
8
f^{-1}(x)=2 x-8
f
−
1
(
x
)
=
2
x
−
8
\newline
f
−
1
(
x
)
=
2
x
−
4
f^{-1}(x)=2 x-4
f
−
1
(
x
)
=
2
x
−
4
Get tutor help
Given
x
>
0
x>0
x
>
0
, the expression
x
9
8
\sqrt[8]{x^{9}}
8
x
9
is equivalent to
\newline
x
2
x
2
8
x^{2} \sqrt[8]{x^{2}}
x
2
8
x
2
\newline
x
2
x
8
x^{2} \sqrt[8]{x}
x
2
8
x
\newline
x
x
8
x \sqrt[8]{x}
x
8
x
\newline
x
x
2
8
x \sqrt[8]{x^{2}}
x
8
x
2
Get tutor help
Given
x
>
0
x>0
x
>
0
, the expression
x
73
8
\sqrt[8]{x^{73}}
8
x
73
is equivalent to
\newline
x
9
x
2
8
x^{9} \sqrt[8]{x^{2}}
x
9
8
x
2
\newline
x
10
x
2
8
x^{10 \sqrt[8]{x^{2}}}
x
10
8
x
2
\newline
x
10
x
8
x^{10} \sqrt[8]{x}
x
10
8
x
\newline
x
9
x
8
x^{9} \sqrt[8]{x}
x
9
8
x
Get tutor help
Solve for all values of
x
x
x
.
\newline
x
10
=
10
x
\frac{x}{10}=\frac{10}{x}
10
x
=
x
10
\newline
Answer:
x
=
x=
x
=
Get tutor help
Given
x
>
0
x>0
x
>
0
, the expression
x
43
6
\sqrt[6]{x^{43}}
6
x
43
is equivalent to
\newline
x
7
x
6
x^{7} \sqrt[6]{x}
x
7
6
x
\newline
x
8
x
6
x^{8} \sqrt[6]{x}
x
8
6
x
\newline
x
8
x^{8}
x
8
\newline
x
7
x^{7}
x
7
Get tutor help
Given
x
>
0
x>0
x
>
0
, the expression
x
15
5
\sqrt[5]{x^{15}}
5
x
15
is equivalent to
\newline
x
3
x^{3}
x
3
\newline
x
2
x^{2}
x
2
\newline
x
2
x
3
5
x^{2} \sqrt[5]{x^{3}}
x
2
5
x
3
\newline
x
3
x
3
5
x^{3} \sqrt[5]{x^{3}}
x
3
5
x
3
Get tutor help
Given
x
>
0
x>0
x
>
0
, the expression
x
10
7
\sqrt[7]{x^{10}}
7
x
10
is equivalent to
\newline
x
2
x
3
7
x^{2} \sqrt[7]{x^{3}}
x
2
7
x
3
\newline
x
x
3
7
x \sqrt[7]{x^{3}}
x
7
x
3
\newline
x
2
x^{2}
x
2
\newline
x
x
x
Get tutor help
Given
x
>
0
x>0
x
>
0
, the expression
x
8
4
\sqrt[4]{x^{8}}
4
x
8
is equivalent to
\newline
x
x
x
\newline
x
x
2
4
x \sqrt[4]{x^{2}}
x
4
x
2
\newline
x
2
x
2
4
x^{2} \sqrt[4]{x^{2}}
x
2
4
x
2
\newline
x
2
x^{2}
x
2
Get tutor help
Given
x
>
0
x>0
x
>
0
, the expression
x
77
9
\sqrt[9]{x^{77}}
9
x
77
is equivalent to
\newline
x
9
x^{9}
x
9
\newline
x
8
x
6
9
x^{8} \sqrt[9]{x^{6}}
x
8
9
x
6
\newline
x
8
x
5
9
x^{8} \sqrt[9]{x^{5}}
x
8
9
x
5
\newline
x
8
x^{8}
x
8
Get tutor help
Given
x
>
0
x>0
x
>
0
, the expression
x
48
8
\sqrt[8]{x^{48}}
8
x
48
is equivalent to
\newline
x
6
x
8
x^{6} \sqrt[8]{x}
x
6
8
x
\newline
x
5
x^{5}
x
5
\newline
x
6
x^{6}
x
6
\newline
x
5
x
8
x^{5} \sqrt[8]{x}
x
5
8
x
Get tutor help
Given
x
>
0
x>0
x
>
0
, the expression
x
18
3
\sqrt[3]{x^{18}}
3
x
18
is equivalent to
\newline
x
5
x
2
3
x^{5} \sqrt[3]{x^{2}}
x
5
3
x
2
\newline
x
6
x^{6}
x
6
\newline
x
6
x
2
3
x^{6} \sqrt[3]{x^{2}}
x
6
3
x
2
\newline
x
5
x^{5}
x
5
Get tutor help
Given
x
>
0
x>0
x
>
0
, the expression
x
53
7
\sqrt[7]{x^{53}}
7
x
53
is equivalent to
\newline
x
7
x^{7}
x
7
\newline
x
6
x
4
7
x^{6} \sqrt[7]{x^{4}}
x
6
7
x
4
\newline
x
8
x^{8}
x
8
\newline
x
7
x
4
7
x^{7} \sqrt[7]{x^{4}}
x
7
7
x
4
Get tutor help
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