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Given 
x > 0, the expression 
root(5)(x^(15)) is equivalent to

x^(3)

x^(2)

x^(2)root(5)(x^(3))

x^(3)root(5)(x^(3))

Given x>0 , the expression x155 \sqrt[5]{x^{15}} is equivalent to\newlinex3 x^{3} \newlinex2 x^{2} \newlinex2x35 x^{2} \sqrt[5]{x^{3}} \newlinex3x35 x^{3} \sqrt[5]{x^{3}}

Full solution

Q. Given x>0 x>0 , the expression x155 \sqrt[5]{x^{15}} is equivalent to\newlinex3 x^{3} \newlinex2 x^{2} \newlinex2x35 x^{2} \sqrt[5]{x^{3}} \newlinex3x35 x^{3} \sqrt[5]{x^{3}}
  1. Rewrite expression as power: We are given the expression x155\sqrt[5]{x^{15}} and we need to simplify it. The 5th5^{\text{th}} root of a number is the same as raising that number to the power of 15\frac{1}{5}. So, we can rewrite the expression as (x15)15(x^{15})^{\frac{1}{5}}.
  2. Apply exponent property: Using the property of exponents that (am)n=amn(a^m)^n = a^{m*n}, we can simplify the expression further. We multiply the exponents 1515 and 15\frac{1}{5} together.
  3. Calculate exponent product: Calculating the product of the exponents gives us 15×(1/5)=315 \times (1/5) = 3. So, the expression becomes x15×(1/5)x^{15\times(1/5)} which is x3x^3.
  4. Final simplified expression: Since x > 0, we don't need to worry about the expression being undefined or taking an even root of a negative number. Therefore, the simplified expression is x3x^3.

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