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Find the inverse function of the function $f(x)=2 x^{\frac{9}{7}}$ on the domain $x \geq 0$.$\newline$$f^{-1}(x)=\left(\frac{x}{2}\right)^{\frac{7}{9}}$$\newline$$f^{-1}(x)=\left(\frac{x}{2}\right)^{-\frac{7}{9}}$$\newline$$f^{-1}(x)=\frac{x^{-\frac{7}{9}}}{2}$$\newline$$f^{-1}(x)=\frac{x^{\frac{7}{9}}}{2}$