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Math Problems
Algebra 1
Multiply two binomials
Express as a trinomial.
\newline
(
2
x
−
5
)
(
x
+
1
)
(2 x-5)(x+1)
(
2
x
−
5
)
(
x
+
1
)
\newline
Answer:
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Express as a trinomial.
\newline
(
2
x
+
2
)
(
3
x
−
2
)
(2 x+2)(3 x-2)
(
2
x
+
2
)
(
3
x
−
2
)
\newline
Answer:
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Express as a trinomial.
\newline
(
2
x
−
6
)
(
x
−
8
)
(2 x-6)(x-8)
(
2
x
−
6
)
(
x
−
8
)
\newline
Answer:
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Express as a trinomial.
\newline
(
x
+
4
)
(
x
−
3
)
(x+4)(x-3)
(
x
+
4
)
(
x
−
3
)
\newline
Answer:
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Express as a trinomial.
\newline
(
3
x
−
3
)
(
2
x
−
5
)
(3 x-3)(2 x-5)
(
3
x
−
3
)
(
2
x
−
5
)
\newline
Answer:
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Express as a trinomial.
\newline
(
x
+
2
)
(
2
x
+
2
)
(x+2)(2 x+2)
(
x
+
2
)
(
2
x
+
2
)
\newline
Answer:
Get tutor help
Express as a trinomial.
\newline
(
2
x
−
9
)
(
3
x
−
6
)
(2 x-9)(3 x-6)
(
2
x
−
9
)
(
3
x
−
6
)
\newline
Answer:
Get tutor help
Express as a trinomial.
\newline
(
x
+
9
)
(
2
x
−
1
)
(x+9)(2 x-1)
(
x
+
9
)
(
2
x
−
1
)
\newline
Answer:
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Express as a trinomial.
\newline
(
2
x
−
10
)
(
2
x
−
2
)
(2 x-10)(2 x-2)
(
2
x
−
10
)
(
2
x
−
2
)
\newline
Answer:
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Express as a trinomial.
\newline
(
x
−
3
)
(
2
x
+
8
)
(x-3)(2 x+8)
(
x
−
3
)
(
2
x
+
8
)
\newline
Answer:
Get tutor help
Express as a trinomial.
\newline
(
2
x
−
10
)
(
3
x
−
5
)
(2 x-10)(3 x-5)
(
2
x
−
10
)
(
3
x
−
5
)
\newline
Answer:
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Express as a trinomial.
\newline
(
x
−
4
)
(
2
x
+
2
)
(x-4)(2 x+2)
(
x
−
4
)
(
2
x
+
2
)
\newline
Answer:
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Express as a trinomial.
\newline
(
3
x
−
9
)
(
3
x
−
3
)
(3 x-9)(3 x-3)
(
3
x
−
9
)
(
3
x
−
3
)
\newline
Answer:
Get tutor help
Express as a trinomial.
\newline
(
2
x
+
5
)
(
3
x
+
2
)
(2 x+5)(3 x+2)
(
2
x
+
5
)
(
3
x
+
2
)
\newline
Answer:
Get tutor help
Express as a trinomial.
\newline
(
x
+
7
)
(
x
+
9
)
(x+7)(x+9)
(
x
+
7
)
(
x
+
9
)
\newline
Answer:
Get tutor help
Express as a trinomial.
\newline
(
x
−
9
)
(
2
x
−
9
)
(x-9)(2 x-9)
(
x
−
9
)
(
2
x
−
9
)
\newline
Answer:
Get tutor help
Express as a trinomial.
\newline
(
2
x
−
5
)
(
3
x
−
5
)
(2 x-5)(3 x-5)
(
2
x
−
5
)
(
3
x
−
5
)
\newline
Answer:
Get tutor help
Express
(
x
−
9
)
2
(x-9)^{2}
(
x
−
9
)
2
as a trinomial in standard form.
\newline
Answer:
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Express
(
x
−
3
)
2
(x-3)^{2}
(
x
−
3
)
2
as a trinomial in standard form.
\newline
Answer:
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Express
(
x
−
6
)
2
(x-6)^{2}
(
x
−
6
)
2
as a trinomial in standard form.
\newline
Answer:
Get tutor help
Express
(
x
+
1
)
2
(x+1)^{2}
(
x
+
1
)
2
as a trinomial in standard form.
\newline
Answer:
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
−
4
(
x
+
8
)
(
x
−
2
)
y=-4(x+8)(x-2)
y
=
−
4
(
x
+
8
)
(
x
−
2
)
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
−
7
(
x
+
9
)
(
x
−
1
)
y=-7(x+9)(x-1)
y
=
−
7
(
x
+
9
)
(
x
−
1
)
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
7
(
x
+
9
)
(
x
+
1
)
y=7(x+9)(x+1)
y
=
7
(
x
+
9
)
(
x
+
1
)
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
−
(
x
−
7
)
(
x
+
6
)
y=-(x-7)(x+6)
y
=
−
(
x
−
7
)
(
x
+
6
)
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
−
8
(
x
−
4
)
(
x
+
3
)
y=-8(x-4)(x+3)
y
=
−
8
(
x
−
4
)
(
x
+
3
)
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
5
(
x
−
2
)
(
x
−
1
)
y=5(x-2)(x-1)
y
=
5
(
x
−
2
)
(
x
−
1
)
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
−
(
x
+
4
)
(
x
−
9
)
y=-(x+4)(x-9)
y
=
−
(
x
+
4
)
(
x
−
9
)
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
−
5
(
x
−
2
)
(
x
−
5
)
y=-5(x-2)(x-5)
y
=
−
5
(
x
−
2
)
(
x
−
5
)
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
4
(
x
−
2
)
(
x
+
6
)
y=4(x-2)(x+6)
y
=
4
(
x
−
2
)
(
x
+
6
)
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
9
(
x
−
2
)
(
x
+
5
)
y=9(x-2)(x+5)
y
=
9
(
x
−
2
)
(
x
+
5
)
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
−
(
x
+
9
)
(
x
−
8
)
y=-(x+9)(x-8)
y
=
−
(
x
+
9
)
(
x
−
8
)
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
6
(
x
+
1
)
(
x
+
3
)
y=6(x+1)(x+3)
y
=
6
(
x
+
1
)
(
x
+
3
)
\newline
Answer:
y
=
y=
y
=
Get tutor help
Find the product. Simplify your answer.
\newline
(
s
+
3
)
(
s
−
3
)
(s+3)(s-3)
(
s
+
3
)
(
s
−
3
)
Get tutor help
Find the square. Simplify your answer.
\newline
(
b
+
4
)
2
(b+4)^2
(
b
+
4
)
2
Get tutor help
Expand.
\newline
Your answer should be a polynomial in standard form.
\newline
(
7
g
+
2
)
(
5
g
+
4
)
=
(7g+2)(5g+4)=
(
7
g
+
2
)
(
5
g
+
4
)
=
Get tutor help
Expand.
\newline
Your answer should be a polynomial in standard form.
\newline
(
1
−
5
z
)
(
2
−
5
z
)
=
(1-5z)(2-5z)=
(
1
−
5
z
)
(
2
−
5
z
)
=
Get tutor help
Expand.
\newline
Your answer should be a polynomial in standard form.
\newline
(
x
+
2
)
(
x
+
5
)
=
(x+2)(x+5)=
(
x
+
2
)
(
x
+
5
)
=
Get tutor help
Expand.
\newline
Your answer should be a polynomial in standard form.
\newline
(
x
+
2
)
(
x
+
3
)
=
(x+2)(x+3)=
(
x
+
2
)
(
x
+
3
)
=
Get tutor help
Expand.
\newline
Your answer should be a polynomial in standard form.
\newline
(
5
+
w
)
(
w
+
4
)
=
(5+w)(w+4)=
(
5
+
w
)
(
w
+
4
)
=
Get tutor help
Expand.
\newline
Your answer should be a polynomial in standard form.
\newline
(
3
b
−
4
)
(
b
+
2
)
=
(3b-4)(b+2)=
(
3
b
−
4
)
(
b
+
2
)
=
Get tutor help
Expand.
\newline
Your answer should be a polynomial in standard form.
\newline
(
x
−
7
)
(
x
−
3
)
=
(x-7)(x-3)=
(
x
−
7
)
(
x
−
3
)
=
Get tutor help
Expand.
\newline
Your answer should be a polynomial in standard form.
\newline
(
x
+
5
)
(
x
+
3
)
=
(x+5)(x+3)=
(
x
+
5
)
(
x
+
3
)
=
Get tutor help
Expand.
\newline
Your answer should be a polynomial in standard form.
\newline
(
x
−
4
)
(
x
−
6
)
=
(x-4)(x-6)=
(
x
−
4
)
(
x
−
6
)
=
Get tutor help
Expand.
\newline
Your answer should be a polynomial in standard form.
\newline
(
x
+
1
)
(
x
−
6
)
=
(x+1)(x-6)=
(
x
+
1
)
(
x
−
6
)
=
Get tutor help
Expand.
\newline
Your answer should be a polynomial in standard form.
\newline
(
x
+
3
)
(
x
−
5
)
=
(x+3)(x-5)=
(
x
+
3
)
(
x
−
5
)
=
Get tutor help
Expand.
\newline
Your answer should be a polynomial in standard form.
\newline
(
x
−
9
)
(
x
+
2
)
=
(x-9)(x+2)=
(
x
−
9
)
(
x
+
2
)
=
Get tutor help
Expand.
\newline
Your answer should be a polynomial in standard form.
\newline
(
6
f
−
7
)
(
8
f
−
9
)
=
(6f-7)(8f-9)=
(
6
f
−
7
)
(
8
f
−
9
)
=
Get tutor help
Expand.
\newline
Your answer should be a polynomial in standard form.
\newline
(
x
+
1
)
(
x
+
8
)
=
(x+1)(x+8)=
(
x
+
1
)
(
x
+
8
)
=
Get tutor help
Expand.
\newline
Your answer should be a polynomial in standard form.
\newline
(
x
−
1
)
(
x
+
4
)
=
(x-1)(x+4)=
(
x
−
1
)
(
x
+
4
)
=
Get tutor help
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