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Expand.
Your answer should be a polynomial in standard form.

(x+1)(x-6)=

Expand.\newlineYour answer should be a polynomial in standard form.\newline(x+1)(x6)=(x+1)(x-6)=

Full solution

Q. Expand.\newlineYour answer should be a polynomial in standard form.\newline(x+1)(x6)=(x+1)(x-6)=
  1. Apply distributive property: Apply the distributive property (also known as the FOIL method) to expand the expression (x+1)(x6)(x+1)(x-6).\newlineFirst, multiply the first terms in each binomial: x×x=x2x \times x = x^2.
  2. Multiply first terms: Multiply the outer terms in the binomials: x(6)=6xx \cdot (-6) = -6x.
  3. Multiply outer terms: Multiply the inner terms in the binomials: 1×x=x1 \times x = x.
  4. Multiply inner terms: Multiply the last terms in each binomial: 1×(6)=61 \times (-6) = -6.
  5. Multiply last terms: Combine the products from steps 11 to 44 to get the expanded form: x26x+x6x^2 - 6x + x - 6.
  6. Combine products: Combine like terms in the expression: x26x+x6=x25x6x^2 - 6x + x - 6 = x^2 - 5x - 6.

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