Re-write the quadratic function below in Standard Form y=4(x-2)(x+6) Answer: y=

Expand Quadratic Function: Expand the quadratic function using the distributive property (FOIL method). We need to multiply the two binomials (x-2) and (x+6) together and then multiply the result by 4.Multiply Binomials: Multiply the terms in the binomials. (x-2)(x+6) = x*x + x*6 - 2*x - 2*6 = x^2 + 6x - 2x - 12 = x^2 + 4x - 12Multiply by 4: Multiply the result by 4. y = 4(x^2 + 4x - 12) y = 4*x^2 + 4*4x - 4*12 y = 4x^2 + 16x - 48

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Re-write the quadratic function below in Standard Form

y=4(x-2)(x+6)
Answer:
y=

Re-write the quadratic function below in Standard Form $\newline$ $y=4(x-2)(x+6)$ $\newline$ Answer: $y=$

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Algebra 1

Multiply two binomials

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Q. Re-write the quadratic function below in Standard Form

\newline

y=4(x-2)(x+6)

\newline

Answer:

y=

Expand Quadratic Function: Expand the quadratic function using the distributive property (FOIL method). We need to multiply the two binomials $(x-2)$ and $(x+6)$ together and then multiply the result by $4$ .
Multiply Binomials: Multiply the terms in the binomials. $\newline$ $(x-2)(x+6) = x\times x + x\times 6 - 2\times x - 2\times 6$ $\newline$ $= x^2 + 6x - 2x - 12$ $\newline$ $= x^2 + 4x - 12$
Multiply by $4$ : Multiply the result by $4$ . $\newline$ $y = 4(x^2 + 4x - 12)$ $\newline$ $y = 4\cdot x^2 + 4\cdot 4x - 4\cdot 12$ $\newline$ $y = 4x^2 + 16x - 48$