Find the square. Simplify your answer. (b+4)^(2)

Identify Special Case: Identify the special case that applies to this problem. (b+4)^2 is in the form of (a + b)^2. Special case: (a + b)^2 = a^2 + 2ab + b^2Identify Values of a and b: Identify the values of a and b. Compare (b+4)^2 with (a + b)^2. a = b b = 4Apply Binomial Formula: Apply the square of a binomial formula to expand (b+4)^2. (a + b)^2 = a^2 + 2ab + b^2 (b+4)^2 = b^2 + 2(b)(4) + 4^2Simplify Expression: Simplify b^2 + 2(b)(4) + 4^2. b^2 + 2(b)(4) + 4^2 = b^2 + (2 * 4)b + 4 * 4 = b^2 + 8b + 16

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Find the square. Simplify your answer. $\newline$ $(b+4)^2$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the square. Simplify your answer.

\newline

(b+4)^2

Identify Special Case: Identify the special case that applies to this problem. $\newline$ $(b+4)^2$ is in the form of $(a + b)^2$ . $\newline$ Special case: $(a + b)^2 = a^2 + 2ab + b^2$
Identify Values of $a$ and $b$ : Identify the values of $a$ and $b$ . Compare $(b+4)^2$ with $(a + b)^2$ . $a = b$ $b = 4$
Apply Binomial Formula: Apply the square of a binomial formula to expand $(b+4)^2$ . $(a + b)^2 = a^2 + 2ab + b^2$ $(b+4)^2 = b^2 + 2(b)(4) + 4^2$
Simplify Expression: Simplify $b^2 + 2(b)(4) + 4^2$ .
$b^2 + 2(b)(4) + 4^2$
$= b^2 + (2 \times 4)b + 4 \times 4$
$= b^2 + 8b + 16$