Re-write the quadratic function below in Standard Form y=6(x+1)(x+3) Answer: y=

Expand Binomials: Expand the first binomial (x+1) with the second binomial (x+3). (x+1)(x+3) = x(x+3) + 1(x+3) = x^2 + 3x + x + 3 = x^2 + 4x + 3Multiply Expanded Binomial: Now, multiply the entire expanded binomial by 6 to get the quadratic function in standard form. y = 6(x^2 + 4x + 3) = 6x^2 + 24x + 18

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Re-write the quadratic function below in Standard Form

y=6(x+1)(x+3)
Answer:
y=

Re-write the quadratic function below in Standard Form $\newline$ $y=6(x+1)(x+3)$ $\newline$ Answer: $y=$

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Algebra 1

Multiply two binomials

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Q. Re-write the quadratic function below in Standard Form

\newline

y=6(x+1)(x+3)

\newline

Answer:

y=

Expand Binomials: Expand the first binomial $(x+1)$ with the second binomial $(x+3)$ . $(x+1)(x+3) = x(x+3) + 1(x+3)$ $= x^2 + 3x + x + 3$ $= x^2 + 4x + 3$
Multiply Expanded Binomial: Now, multiply the entire expanded binomial by $6$ to get the quadratic function in standard form. $\newline$ $y = 6(x^2 + 4x + 3)$ $\newline$ $= 6x^2 + 24x + 18$