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Let’s check out your problem:
Expand.
\newline
Your answer should be a polynomial in standard form.
\newline
(
x
+
3
)
(
x
−
5
)
=
(x+3)(x-5)=
(
x
+
3
)
(
x
−
5
)
=
View step-by-step help
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Math Problems
Algebra 1
Multiply two binomials
Full solution
Q.
Expand.
\newline
Your answer should be a polynomial in standard form.
\newline
(
x
+
3
)
(
x
−
5
)
=
(x+3)(x-5)=
(
x
+
3
)
(
x
−
5
)
=
Multiply First terms:
Multiply the First terms:
x
×
x
=
x
2
x \times x = x^2
x
×
x
=
x
2
.
Multiply Outer terms:
Multiply the Outer terms:
x
⋅
(
−
5
)
=
−
5
x
x \cdot (-5) = -5x
x
⋅
(
−
5
)
=
−
5
x
.
Multiply Inner terms:
Multiply the Inner terms:
3
×
x
=
3
x
3 \times x = 3x
3
×
x
=
3
x
.
Multiply Last terms:
Multiply the Last terms:
3
×
(
−
5
)
=
−
15
3 \times (-5) = -15
3
×
(
−
5
)
=
−
15
.
Combine all the products:
Combine all the products:
x
2
−
5
x
+
3
x
−
15
x^2 - 5x + 3x - 15
x
2
−
5
x
+
3
x
−
15
.
Combine like terms:
Combine like terms:
−
5
x
-5x
−
5
x
and
3
x
3x
3
x
add up to
−
2
x
-2x
−
2
x
.
\newline
So, the expression becomes
x
2
−
2
x
−
15
x^2 - 2x - 15
x
2
−
2
x
−
15
.
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\newline
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\newline
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x
)
=
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q
(
x
)
=
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−
9
even, odd, or neither?
\newline
Choices:
\newline
[[even][odd][neither]]
\text{[[even][odd][neither]]}
[[even][odd][neither]]
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\newline
(
r
+
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)
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r
+
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)
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(
r
+
3
)
(
4
r
+
2
)
\newline
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Question
Find the roots of the factored polynomial.
\newline
(
x
+
7
)
(
x
+
4
)
(x + 7)(x + 4)
(
x
+
7
)
(
x
+
4
)
\newline
Write your answer as a list of values separated by commas.
\newline
x
=
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