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Expand.
Your answer should be a polynomial in standard form.

(7g+2)(5g+4)=

Expand.\newlineYour answer should be a polynomial in standard form.\newline(7g+2)(5g+4)=(7g+2)(5g+4)=

Full solution

Q. Expand.\newlineYour answer should be a polynomial in standard form.\newline(7g+2)(5g+4)=(7g+2)(5g+4)=
  1. Apply distributive property: Apply the distributive property (also known as the FOIL method) to expand the expression (7g+2)(5g+4)(7g+2)(5g+4).\newlineFirst, multiply the first terms in each binomial: 7g×5g=35g27g \times 5g = 35g^2.
  2. Multiply first terms: Multiply the outer terms in the binomials: 7g×4=28g7g \times 4 = 28g.
  3. Multiply outer terms: Multiply the inner terms in the binomials: 2×5g=10g2 \times 5g = 10g.
  4. Multiply inner terms: Multiply the last terms in each binomial: 2×4=82 \times 4 = 8.
  5. Multiply last terms: Combine the products from steps 11 to 44 to get the expanded form: 35g2+28g+10g+835g^2 + 28g + 10g + 8.
  6. Combine products: Combine like terms 28g28g and 10g10g to get the polynomial in standard form.35g2+28g+10g+8=35g2+(28g+10g)+8=35g2+38g+8.35g^2 + 28g + 10g + 8 = 35g^2 + (28g + 10g) + 8 = 35g^2 + 38g + 8.

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