Find the product. Simplify your answer. (s+3)(s-3)

Identify Special Case: Identify the special case that applies here. (s+3)(s-3) is in the form of (a + b)(a - b). Special case: (a + b)(a - b) = a^2 - b^2Identify Values of a and b: Identify the values of a and b. Compare (s+3)(s-3) with (a + b)(a - b). a = s b = 3Apply Difference of Squares: Apply the difference of squares to expand (s+3)(s-3). (a + b)(a - b) = a^2 - b^2 (s+3)(s-3) = s^2 - 3^2Simplify Expression: Simplify s^2 - 3^2. s^2 - 3^2 = s^2 - 9

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Find the product. Simplify your answer. $\newline$ $(s+3)(s-3)$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(s+3)(s-3)

Identify Special Case: Identify the special case that applies here. $\newline$ $(s+3)(s-3)$ is in the form of $(a + b)(a - b)$ . $\newline$ Special case: $(a + b)(a - b) = a^2 - b^2$
Identify Values of a and b: Identify the values of $a$ and $b$ . Compare $(s+3)(s-3)$ with $(a + b)(a - b)$ . $a = s$ $b = 3$
Apply Difference of Squares: Apply the difference of squares to expand $(s+3)(s-3)$ . $\newline$ $(a + b)(a - b) = a^2 - b^2$ $\newline$ $(s+3)(s-3) = s^2 - 3^2$
Simplify Expression: Simplify $s^2 - 3^2$ . $\newline$ $s^2 - 3^2 = s^2 - 9$