Re-write the quadratic function below in Standard Form y=5(x-2)(x-1) Answer: y=

Expand Quadratic Function: Expand the quadratic function using the distributive property (also known as the FOIL method for binomials). We have y = 5(x - 2)(x - 1). First, we'll multiply the terms inside the parentheses. (x - 2)(x - 1) = x(x - 1) - 2(x - 1) = x^2 - x - 2x + 2 = x^2 - 3x + 2Multiply Expanded Binomial: Multiply the expanded binomial by the coefficient 5. Now we multiply each term of the binomial by 5 to get the quadratic function in standard form. y = 5(x^2 - 3x + 2) = 5x^2 - 15x + 10Final Standard Form: Write the final answer in Standard Form. The Standard Form of a quadratic function is y = ax^2 + bx + c. Our function is now in this form, with a = 5, b = -15, and c = 10. y = 5x^2 - 15x + 10

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Re-write the quadratic function below in Standard Form

y=5(x-2)(x-1)
Answer:
y=

Re-write the quadratic function below in Standard Form $\newline$ $y=5(x-2)(x-1)$ $\newline$ Answer: $y=$

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Algebra 1

Multiply two binomials

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Q. Re-write the quadratic function below in Standard Form

\newline

y=5(x-2)(x-1)

\newline

Answer:

y=

Expand Quadratic Function: Expand the quadratic function using the distributive property (also known as the FOIL method for binomials). $\newline$ We have $y = 5(x - 2)(x - 1)$ . First, we'll multiply the terms inside the parentheses. $\newline$ $(x - 2)(x - 1) = x(x - 1) - 2(x - 1)$ $\newline$ $= x^2 - x - 2x + 2$ $\newline$ $= x^2 - 3x + 2$
Multiply Expanded Binomial: Multiply the expanded binomial by the coefficient $5$ . Now we multiply each term of the binomial by $5$ to get the quadratic function in standard form. $y = 5(x^2 - 3x + 2) = 5x^2 - 15x + 10$
Final Standard Form: Write the final answer in Standard Form. $\newline$ The Standard Form of a quadratic function is $y = ax^2 + bx + c$ . Our function is now in this form, with $a = 5$ , $b = -15$ , and $c = 10$ . $\newline$ $y = 5x^2 - 15x + 10$