Re-write the quadratic function below in Standard Form y=-5(x-2)(x-5) Answer: y=

Simplify Terms: Now, we will simplify the expression inside the brackets by multiplying the terms. y = -5[x^2 - 5x - 2x + 10] Combine like terms inside the brackets. y = -5[x^2 - 7x + 10]Distribute -5: Next, distribute the -5 across each term inside the brackets to get the standard form of the quadratic equation. y = -5(x^2) + 5(7x) - 5(10) y = -5x^2 + 35x - 50Standard Form: We have now written the quadratic function in standard form, which is y = ax^2 + bx + c, where a, b, and c are constants. The standard form of the given quadratic function is y = -5x^2 + 35x - 50.

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Re-write the quadratic function below in Standard Form

y=-5(x-2)(x-5)
Answer:
y=

Re-write the quadratic function below in Standard Form $\newline$ $y=-5(x-2)(x-5)$ $\newline$ Answer: $y=$

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Algebra 1

Multiply two binomials

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Q. Re-write the quadratic function below in Standard Form

\newline

y=-5(x-2)(x-5)

\newline

Answer:

y=

Simplify Terms: Now, we will simplify the expression inside the brackets by multiplying the terms. $\newline$ $y = -5[x^2 - 5x - 2x + 10]$ $\newline$ Combine like terms inside the brackets. $\newline$ $y = -5[x^2 - 7x + 10]$
Distribute $-5$ : Next, distribute the $-5$ across each term inside the brackets to get the standard form of the quadratic equation. $\newline$ $y = -5(x^2) + 5(7x) - 5(10)$ $\newline$ $y = -5x^2 + 35x - 50$
Standard Form: We have now written the quadratic function in standard form, which is $y = ax^2 + bx + c$ , where $a$ , $b$ , and $c$ are constants. $\newline$ The standard form of the given quadratic function is $y = -5x^2 + 35x - 50$ .