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Re-write the quadratic function below in Standard Form

y=-8(x-4)(x+3)
Answer: 
y=

Re-write the quadratic function below in Standard Form\newliney=8(x4)(x+3) y=-8(x-4)(x+3) \newlineAnswer: y= y=

Full solution

Q. Re-write the quadratic function below in Standard Form\newliney=8(x4)(x+3) y=-8(x-4)(x+3) \newlineAnswer: y= y=
  1. Apply Distributive Property: First, apply the distributive property (also known as the FOIL method) to expand the product of the binomials (x4)(x - 4) and (x+3)(x + 3).y=8(x4)(x+3)y = -8(x - 4)(x + 3)y=8[(x)(x)+(x)(3)(4)(x)(4)(3)]y = -8[(x)(x) + (x)(3) - (4)(x) - (4)(3)]
  2. Perform Multiplication: Next, perform the multiplication for each term.\newliney=8[x2+3x4x12]y = -8[x^2 + 3x - 4x - 12]\newlineCombine like terms (3x3x and 4x-4x) within the brackets.\newliney=8[x2x12]y = -8[x^2 - x - 12]
  3. Combine Like Terms: Now, distribute the 8-8 across each term inside the brackets.\newliney=8(x2)8(x)8(12)y = -8(x^2) - 8(-x) - 8(-12)\newliney=8x2+8x+96y = -8x^2 + 8x + 96
  4. Distribute 8-8: The quadratic function is now in standard form, which is y=ax2+bx+cy = ax^2 + bx + c.\newlineSo, the standard form of the given quadratic function is y=8x2+8x+96y = -8x^2 + 8x + 96.

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