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Math Problems
Grade 8
Powers with negative bases
Factor completely:
\newline
(
x
+
6
)
3
−
(
x
+
6
)
4
(x+6)^{3}-(x+6)^{4}
(
x
+
6
)
3
−
(
x
+
6
)
4
\newline
Answer:
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Factor completely:
\newline
(
7
x
−
5
)
4
+
9
(
7
x
−
5
)
3
(7 x-5)^{4}+9(7 x-5)^{3}
(
7
x
−
5
)
4
+
9
(
7
x
−
5
)
3
\newline
Answer:
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Factor completely:
\newline
9
(
3
x
−
5
)
6
+
(
3
x
−
5
)
7
9(3 x-5)^{6}+(3 x-5)^{7}
9
(
3
x
−
5
)
6
+
(
3
x
−
5
)
7
\newline
Answer:
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Factor completely:
\newline
(
3
x
+
2
)
2
−
(
6
x
−
7
)
2
(3 x+2)^{2}-(6 x-7)^{2}
(
3
x
+
2
)
2
−
(
6
x
−
7
)
2
\newline
Answer:
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Factor completely:
\newline
(
7
x
+
1
)
2
−
(
4
x
+
3
)
2
(7 x+1)^{2}-(4 x+3)^{2}
(
7
x
+
1
)
2
−
(
4
x
+
3
)
2
\newline
Answer:
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Factor completely:
\newline
(
x
+
9
)
2
−
(
5
x
−
4
)
2
(x+9)^{2}-(5 x-4)^{2}
(
x
+
9
)
2
−
(
5
x
−
4
)
2
\newline
Answer:
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Factor completely:
\newline
(
9
x
+
7
)
2
−
(
x
+
1
)
2
(9 x+7)^{2}-(x+1)^{2}
(
9
x
+
7
)
2
−
(
x
+
1
)
2
\newline
Answer:
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Factor completely:
\newline
(
2
x
−
3
)
2
−
(
x
+
6
)
2
(2 x-3)^{2}-(x+6)^{2}
(
2
x
−
3
)
2
−
(
x
+
6
)
2
\newline
Answer:
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Factor completely:
\newline
(
2
x
+
7
)
2
+
3
(
2
x
+
7
)
(2 x+7)^{2}+3(2 x+7)
(
2
x
+
7
)
2
+
3
(
2
x
+
7
)
\newline
Answer:
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Factor completely:
\newline
6
(
x
−
3
)
5
−
(
x
−
3
)
6
6(x-3)^{5}-(x-3)^{6}
6
(
x
−
3
)
5
−
(
x
−
3
)
6
\newline
Answer:
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Factor completely:
\newline
10
(
x
−
6
)
4
−
(
x
−
6
)
5
10(x-6)^{4}-(x-6)^{5}
10
(
x
−
6
)
4
−
(
x
−
6
)
5
\newline
Answer:
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Factor completely:
\newline
(
7
x
+
9
)
6
−
10
(
7
x
+
9
)
5
(7 x+9)^{6}-10(7 x+9)^{5}
(
7
x
+
9
)
6
−
10
(
7
x
+
9
)
5
\newline
Answer:
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Factor completely.
(
x
2
−
4
)
(
x
2
+
6
x
+
9
)
=
(x^2-4)(x^2+6x+9)=
(
x
2
−
4
)
(
x
2
+
6
x
+
9
)
=
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x
+
1
6
x
+
x
+
1
2
x
=
\frac{x+1}{6 x}+\frac{x+1}{2 x}=
6
x
x
+
1
+
2
x
x
+
1
=
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(
−
3
)
0.5
=
(-3)^{0.5}=
(
−
3
)
0.5
=
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(
2
z
−
1
)
(
z
2
−
2
z
+
1
)
=
(2z-1)(z^2-2z+1)=
(
2
z
−
1
)
(
z
2
−
2
z
+
1
)
=
Get tutor help
Evaluate. Write your answer as a whole number or as a simplified fraction.
\newline
(
1
0
9
)
/
(
1
0
7
)
=
(10^{9})/(10^{7})=
(
1
0
9
)
/
(
1
0
7
)
=
Get tutor help
Solve for
y
\mathrm{y}
y
.
\newline
y
−
7
=
5
\frac{y}{-7}=5
−
7
y
=
5
\newline
Answer:
y
=
y=
y
=
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Solve for
t
\mathrm{t}
t
.
\newline
t
−
3
=
8
\frac{t}{-3}=8
−
3
t
=
8
\newline
Answer:
t
=
t=
t
=
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6
÷
2
(
1
+
2
)
=
6 \div 2(1+2)=
6
÷
2
(
1
+
2
)
=
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(
8
−
8
)
(
8
3
)
=
□
(8^{-8})(8^{3})=\Box
(
8
−
8
)
(
8
3
)
=
□
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(
8
−
8
)
(
8
3
)
=
□
(8^{-8})(8^{3})=\Box
(
8
−
8
)
(
8
3
)
=
□
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Evaluate.
\newline
(
−
2
)
2
=
(-2)^{2}=
(
−
2
)
2
=
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Evaluate.
\newline
(
−
8
)
2
=
(-8)^{2}=
(
−
8
)
2
=
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Evaluate.
\newline
(
−
3
)
3
=
(-3)^{3}=
(
−
3
)
3
=
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Evaluate.
\newline
(
−
2
)
5
=
(-2)^{5}=
(
−
2
)
5
=
Get tutor help
Evaluate.
\newline
(
−
5
4
)
2
=
\left(-\frac{5}{4}\right)^{2}=
(
−
4
5
)
2
=
Get tutor help
Evaluate.
\newline
(
−
1
2
3
)
2
=
\left(-1 \frac{2}{3}\right)^{2}=
(
−
1
3
2
)
2
=
Get tutor help
Evaluate.
\newline
(
−
2
3
4
)
2
=
\left(-2 \frac{3}{4}\right)^{2}=
(
−
2
4
3
)
2
=
Get tutor help
Evaluate.
\newline
(
−
3
2
3
)
2
=
\left(-3 \frac{2}{3}\right)^{2}=
(
−
3
3
2
)
2
=
Get tutor help
Evaluate.
\newline
−
1
4
=
-1^{4}=
−
1
4
=
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Evaluate.
\newline
(
−
1
)
3
=
(-1)^{3}=
(
−
1
)
3
=
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Evaluate.
\newline
(
−
2
5
)
2
=
\left(-\frac{2}{5}\right)^{2}=
(
−
5
2
)
2
=
Get tutor help
Evaluate.
\newline
(
−
10
)
2
=
(-10)^{2}=
(
−
10
)
2
=
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Evaluate.
\newline
(
−
2
)
3
=
(-2)^{3}=
(
−
2
)
3
=
Get tutor help
Evaluate.
\newline
(
−
1
4
)
2
=
\left(-\frac{1}{4}\right)^{2}=
(
−
4
1
)
2
=
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Evaluate.
\newline
−
1
1
2
=
-11^{2}=
−
1
1
2
=
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Evaluate.
\newline
(
−
4
5
)
2
=
\left(-\frac{4}{5}\right)^{2}=
(
−
5
4
)
2
=
Get tutor help
Evaluate.
\newline
(
−
4
3
)
3
=
\left(-\frac{4}{3}\right)^{3}=
(
−
3
4
)
3
=
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Evaluate.
\newline
−
9
2
=
-9^{2}=
−
9
2
=
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Evaluate.
\newline
−
3
3
=
-3^{3}=
−
3
3
=
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Evaluate.
\newline
−
2
3
=
-2^{3}=
−
2
3
=
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Evaluate.
\newline
−
2
5
=
-2^{5}=
−
2
5
=
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Evaluate.
\newline
−
7
2
=
-7^{2}=
−
7
2
=
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Evaluate.
\newline
−
1
5
=
-1^{5}=
−
1
5
=
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Evaluate.
\newline
(
−
3
)
4
=
(-3)^{4}=
(
−
3
)
4
=
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Evaluate.
\newline
(
−
3
1
2
)
2
=
\left(-3 \frac{1}{2}\right)^{2}=
(
−
3
2
1
)
2
=
Get tutor help
Evaluate.
\newline
(
−
2
2
5
)
2
=
\left(-2 \frac{2}{5}\right)^{2}=
(
−
2
5
2
)
2
=
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Evaluate.
\newline
(
−
2
2
3
)
2
=
\left(-2 \frac{2}{3}\right)^{2}=
(
−
2
3
2
)
2
=
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Evaluate.
\newline
(
−
1
)
5
=
(-1)^{5}=
(
−
1
)
5
=
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