Factor completely: (7x-5)^(4)+9(7x-5)^(3) Answer:

Identify common factor: Identify the common factor in both terms. The expression given is (7x-5)^(4)+9(7x-5)^(3). We can see that (7x-5)^(3) is a common factor in both terms.Factor out common factor: Factor out the common factor (7x-5)^(3). We can write the expression as (7x-5)^(3) * ((7x-5) + 9).Simplify inside parentheses: Simplify the expression inside the parentheses. Now we simplify (7x-5) + 9, which equals 7x + 4.Write final factored form: Write the final factored form. The completely factored form of the expression is (7x-5)^(3) * (7x + 4).

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Factor completely:

(7x-5)^(4)+9(7x-5)^(3)
Answer:

Factor completely: $\newline$ $(7 x-5)^{4}+9(7 x-5)^{3}$ $\newline$ Answer:

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Math Problems

Grade 8

Powers with negative bases

Full solution

Q. Factor completely:

\newline

(7 x-5)^{4}+9(7 x-5)^{3}

\newline

Answer:

Identify common factor: Identify the common factor in both terms. $\newline$ The expression given is $(7x-5)^{4}+9(7x-5)^{3}$ . We can see that $(7x-5)^{3}$ is a common factor in both terms.
Factor out common factor: Factor out the common factor $(7x-5)^{3}$ . $\newline$ We can write the expression as $(7x-5)^{3} \times ((7x-5) + 9)$ .
Simplify inside parentheses: Simplify the expression inside the parentheses. $\newline$ Now we simplify $(7x-5) + 9$ , which equals $7x + 4$ .
Write final factored form: Write the final factored form. $\newline$ The completely factored form of the expression is $(7x-5)^{3} \times (7x + 4)$ .