Factor completely.(x^2-4)(x^2+6x+9)=

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Identify Special Products: Recognize the special products in the expression. The expression (x^2-4)(x^2+6x+9) contains two parts that can be identified as special products. The first part, x^2-4, is a difference of squares. The second part, x^2+6x+9, is a perfect square trinomial.Factor Difference of Squares: Factor the difference of squares. The difference of squares can be factored as (a^2 - b^2) = (a + b)(a - b). In this case, a is x and b is 2. So, x^2 - 4 = (x + 2)(x - 2).Factor Perfect Square Trinomial: Factor the perfect square trinomial. The perfect square trinomial can be factored as (a + b)^2 = a^2 + 2ab + b^2. In this case, a is x and b is 3. So, x^2 + 6x + 9 = (x + 3)^2.Write Factored Expression: Write the expression with the factored parts. Replace the original expression with the factored parts from Step 2 and Step 3. (x^2-4)(x^2+6x+9) = (x + 2)(x - 2)(x + 3)^2.Check for Further Factoring: Check for any further factoring. The expression (x + 2)(x - 2)(x + 3)^2 is already fully factored. There are no common factors to factor out, and each part is in its simplest form.

Factor completely. $(x^2-4)(x^2+6x+9)=$

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Factor completely.(x2−4)(x2+6x+9)=(x^2-4)(x^2+6x+9)=(x2−4)(x2+6x+9)=

Factor completely. $(x^2-4)(x^2+6x+9)=$