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Math Problems
Algebra 2
Inverses of sin, cos, and tan: degrees
0
∘
≤
θ
≤
18
0
∘
0^\circ\leq\theta\leq180^\circ
0
∘
≤
θ
≤
18
0
∘
. Find the value of
θ
\theta
θ
in degrees.
\newline
cos
(
θ
)
=
−
2
/
2
\cos(\theta)= - \sqrt{2}/ 2
cos
(
θ
)
=
−
2
/2
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What is the sign of
−
4
a
b
-4 a b
−
4
ab
when
a
>
0
a>0
a
>
0
and
b
<
0
b<0
b
<
0
?
\newline
Choose
1
1
1
answer:
\newline
(A) Positive
\newline
(B) Negative
\newline
(c) Zero
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What is the sign of
3
x
y
3 x y
3
x
y
when
x
>
0
x>0
x
>
0
and
y
<
0
y<0
y
<
0
?
\newline
Choose
1
1
1
answer:
\newline
(A) Positive
\newline
(B) Negative
\newline
(c) Zero
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What is the sign of
c
÷
d
c \div d
c
÷
d
when
c
>
0
c>0
c
>
0
and
d
<
0
d<0
d
<
0
?
\newline
Choose
1
1
1
answer:
\newline
(A) Positive
\newline
B) Negative
\newline
(c) Zero
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Which of the following is the derivative
d
y
d
x
\frac{d y}{d x}
d
x
d
y
for the plane curve defined by the equations
x
(
t
)
=
−
sin
π
t
x(t)=-\sin \pi t
x
(
t
)
=
−
sin
π
t
,
y
(
t
)
=
cos
π
t
y(t)=\cos \pi t
y
(
t
)
=
cos
π
t
, and
0
≤
t
≤
2
0 \leq t \leq 2
0
≤
t
≤
2
?
\newline
Select the correct answer below:
\newline
(A)
−
cot
π
t
-\cot \pi t
−
cot
π
t
\newline
(B)
cot
π
t
\cot \pi t
cot
π
t
\newline
(C)
π
tan
π
t
\pi \tan \pi t
π
tan
π
t
\newline
(D)
tan
π
t
\tan \pi t
tan
π
t
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State all integer values of
x
x
x
in the interval
0
≤
x
≤
7
0 \leq x \leq 7
0
≤
x
≤
7
that satisfy the following inequality:
\newline
−
2
x
+
4
≥
1
-2 x+4 \geq 1
−
2
x
+
4
≥
1
\newline
Answer:
x
=
x=
x
=
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lim
x
→
0
csc
(
x
)
=
?
\lim _{x \rightarrow 0} \csc (x)=?
x
→
0
lim
csc
(
x
)
=
?
\newline
Choose
1
1
1
answer:
\newline
(A)
−
1
-1
−
1
\newline
(B)
0
0
0
\newline
(C)
1
1
1
\newline
(D) The limit doesn't exist.
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u
⃗
=
(
−
7
,
2
)
\vec{u}=(-7,2)
u
=
(
−
7
,
2
)
\newline
Find the direction angle of
u
⃗
\vec{u}
u
. Enter your answer as an angle in degrees between
0
∘
0^{\circ}
0
∘
and
36
0
∘
360^{\circ}
36
0
∘
rounded to the nearest hundredth.
\newline
θ
=
□
∘
\theta=\square^{\circ}
θ
=
□
∘
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u
⃗
=
(
5
,
8
)
\vec{u}=(5,8)
u
=
(
5
,
8
)
\newline
Find the direction angle of
u
⃗
\vec{u}
u
. Enter your answer as an angle in degrees between
0
∘
0^{\circ}
0
∘
and
36
0
∘
360^{\circ}
36
0
∘
rounded to the nearest hundredth.
\newline
θ
=
□
∘
\theta=\square^{\circ}
θ
=
□
∘
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u
⃗
=
(
2
,
5
)
\vec{u}=(2,5)
u
=
(
2
,
5
)
\newline
Find the direction angle of
u
⃗
\vec{u}
u
. Enter your answer as an angle in degrees between
0
∘
0^{\circ}
0
∘
and
36
0
∘
360^{\circ}
36
0
∘
rounded to the nearest hundredth.
\newline
θ
=
□
∘
\theta=\square^{\circ}
θ
=
□
∘
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u
⃗
=
(
−
1
,
4
)
\vec{u}=(-1,4)
u
=
(
−
1
,
4
)
\newline
Find the direction angle of
u
⃗
\vec{u}
u
. Enter your answer as an angle in degrees between
0
∘
0^{\circ}
0
∘
and
36
0
∘
360^{\circ}
36
0
∘
rounded to the nearest hundredth.
\newline
θ
=
□
∘
\theta=\square^{\circ}
θ
=
□
∘
Get tutor help
u
⃗
=
(
−
2
,
5
)
\vec{u}=(-2,5)
u
=
(
−
2
,
5
)
\newline
Find the direction angle of
u
⃗
\vec{u}
u
. Enter your answer as an angle in degrees between
0
∘
0^{\circ}
0
∘
and
36
0
∘
360^{\circ}
36
0
∘
rounded to the nearest hundredth.
\newline
θ
=
□
∘
\theta=\square^{\circ}
θ
=
□
∘
Get tutor help
u
⃗
=
(
−
9
,
3
)
\vec{u}=(-9,3)
u
=
(
−
9
,
3
)
\newline
Find the direction angle of
u
⃗
\vec{u}
u
. Enter your answer as an angle in degrees between
0
∘
0^{\circ}
0
∘
and
36
0
∘
360^{\circ}
36
0
∘
rounded to the nearest hundredth.
\newline
θ
=
□
∘
\theta=\square^{\circ}
θ
=
□
∘
Get tutor help
u
⃗
=
(
6
,
7
)
\vec{u}=(6,7)
u
=
(
6
,
7
)
\newline
Find the direction angle of
u
⃗
\vec{u}
u
. Enter your answer as an angle in degrees between
0
∘
0^{\circ}
0
∘
and
36
0
∘
360^{\circ}
36
0
∘
rounded to the nearest hundredth.
\newline
θ
=
□
∘
\theta=\square^{\circ}
θ
=
□
∘
Get tutor help
u
⃗
=
(
−
7
,
−
10
)
\vec{u}=(-7,-10)
u
=
(
−
7
,
−
10
)
\newline
Find the direction angle of
u
⃗
\vec{u}
u
. Enter your answer as an angle in degrees between
0
∘
0^{\circ}
0
∘
and
36
0
∘
360^{\circ}
36
0
∘
rounded to the nearest hundredth.
\newline
θ
=
□
∘
\theta=\square^{\circ}
θ
=
□
∘
Get tutor help
u
⃗
=
(
5
,
3
)
\vec{u}=(5,3)
u
=
(
5
,
3
)
\newline
Find the direction angle of
u
⃗
\vec{u}
u
. Enter your answer as an angle in degrees between
0
∘
0^{\circ}
0
∘
and
36
0
∘
360^{\circ}
36
0
∘
rounded to the nearest hundredth.
\newline
θ
=
□
∘
\theta=\square^{\circ}
θ
=
□
∘
Get tutor help
u
⃗
=
(
−
10
,
7
)
\vec{u}=(-10,7)
u
=
(
−
10
,
7
)
\newline
Find the direction angle of
u
⃗
\vec{u}
u
. Enter your answer as an angle in degrees between
0
∘
0^{\circ}
0
∘
and
36
0
∘
360^{\circ}
36
0
∘
rounded to the nearest hundredth.
\newline
θ
=
□
∘
\theta=\square^{\circ}
θ
=
□
∘
Get tutor help
u
⃗
=
(
−
4
,
−
3
)
\vec{u}=(-4,-3)
u
=
(
−
4
,
−
3
)
\newline
Find the direction angle of
u
⃗
\vec{u}
u
. Enter your answer as an angle in degrees between
0
∘
0^{\circ}
0
∘
and
36
0
∘
360^{\circ}
36
0
∘
rounded to the nearest hundredth.
\newline
θ
=
□
∘
\theta=\square^{\circ}
θ
=
□
∘
Get tutor help
u
⃗
=
(
−
10
,
−
9
)
\vec{u}=(-10,-9)
u
=
(
−
10
,
−
9
)
\newline
Find the direction angle of
u
⃗
\vec{u}
u
. Enter your answer as an angle in degrees between
0
∘
0^{\circ}
0
∘
and
36
0
∘
360^{\circ}
36
0
∘
rounded to the nearest hundredth.
\newline
θ
=
□
∘
\theta=\square^{\circ}
θ
=
□
∘
Get tutor help
u
⃗
=
(
8
,
6
)
\vec{u}=(8,6)
u
=
(
8
,
6
)
\newline
Find the direction angle of
u
⃗
\vec{u}
u
. Enter your answer as an angle in degrees between
0
∘
0^{\circ}
0
∘
and
36
0
∘
360^{\circ}
36
0
∘
rounded to the nearest hundredth.
\newline
θ
=
□
∘
\theta= \square^{\circ}
θ
=
□
∘
Get tutor help
u
⃗
=
(
8
,
−
3
)
\vec{u}=(8,-3)
u
=
(
8
,
−
3
)
\newline
Find the direction angle of
u
⃗
\vec{u}
u
. Enter your answer as an angle in degrees between
0
∘
0^{\circ}
0
∘
and
36
0
∘
360^{\circ}
36
0
∘
rounded to the nearest hundredth.
\newline
θ
=
□
∘
\theta= \square^{\circ}
θ
=
□
∘
Get tutor help
u
⃗
=
(
−
8
,
−
9
)
\vec{u}=(-8,-9)
u
=
(
−
8
,
−
9
)
\newline
Find the direction angle of
u
⃗
\vec{u}
u
. Enter your answer as an angle in degrees between
0
∘
0^{\circ}
0
∘
and
36
0
∘
360^{\circ}
36
0
∘
rounded to the nearest hundredth.
\newline
θ
=
□
∘
\theta= \square^{\circ}
θ
=
□
∘
Get tutor help
u
⃗
=
(
6
,
−
8
)
\vec{u}=(6,-8)
u
=
(
6
,
−
8
)
\newline
Find the direction angle of
u
⃗
\vec{u}
u
. Enter your answer as an angle in degrees between
0
∘
0^{\circ}
0
∘
and
36
0
∘
360^{\circ}
36
0
∘
rounded to the nearest hundredth.
\newline
θ
=
□
∘
\theta= \square^{\circ}
θ
=
□
∘
Get tutor help
u
⃗
=
(
9
,
−
6
)
\vec{u}=(9,-6)
u
=
(
9
,
−
6
)
\newline
Find the direction angle of
u
⃗
\vec{u}
u
. Enter your answer as an angle in degrees between
0
∘
0^{\circ}
0
∘
and
36
0
∘
360^{\circ}
36
0
∘
rounded to the nearest hundredth.
\newline
θ
=
□
∘
\theta= \square^{\circ}
θ
=
□
∘
Get tutor help
u
⃗
=
(
4
,
−
2
)
\vec{u}=(4,-2)
u
=
(
4
,
−
2
)
\newline
Find the direction angle of
u
⃗
\vec{u}
u
. Enter your answer as an angle in degrees between
0
∘
0^{\circ}
0
∘
and
36
0
∘
360^{\circ}
36
0
∘
rounded to the nearest hundredth.
\newline
θ
=
□
∘
\theta= \square^{\circ}
θ
=
□
∘
Get tutor help
u
⃗
=
(
7
,
−
4
)
\vec{u}=(7,-4)
u
=
(
7
,
−
4
)
\newline
Find the direction angle of
u
⃗
\vec{u}
u
. Enter your answer as an angle in degrees between
0
∘
0^{\circ}
0
∘
and
36
0
∘
360^{\circ}
36
0
∘
rounded to the nearest hundredth.
\newline
θ
=
□
∘
\theta= \square^{\circ}
θ
=
□
∘
Get tutor help
u
⃗
=
(
−
5
,
−
8
)
\vec{u}=(-5,-8)
u
=
(
−
5
,
−
8
)
\newline
Find the direction angle of
u
⃗
\vec{u}
u
. Enter your answer as an angle in degrees between
0
∘
0^{\circ}
0
∘
and
36
0
∘
360^{\circ}
36
0
∘
rounded to the nearest hundredth.
\newline
θ
=
□
∘
\theta= \square^{\circ}
θ
=
□
∘
Get tutor help
If
θ
=
4
π
9
\theta=\frac{4 \pi}{9}
θ
=
9
4
π
radians, what is the value of
θ
\theta
θ
in degrees?
\newline
Choose
1
1
1
answer:
\newline
(A)
2
0
∘
20^{\circ}
2
0
∘
\newline
(B)
3
6
∘
36^{\circ}
3
6
∘
\newline
(C)
8
0
∘
80^{\circ}
8
0
∘
\newline
(D)
72
0
∘
720^{\circ}
72
0
∘
Get tutor help
−
9
0
∘
<
θ
<
9
0
∘
-90^\circ < \theta < 90^\circ
−
9
0
∘
<
θ
<
9
0
∘
. Find the value of
θ
\theta
θ
in degrees.
\newline
tan
(
θ
)
=
0
\tan(\theta) = 0
tan
(
θ
)
=
0
\newline
Write your answer in simplified, rationalized form. Do not round.
\newline
θ
=
\theta =
θ
=
____
∘
^\circ
∘
\newline
Get tutor help
