State all integer values of x in the interval 0 = 1 Answer: x=

Solve for x: First, we need to solve the inequality for x. -2x + 4 >= 1 Subtract 4 from both sides to isolate the term containing x. -2x + 4 - 4 >= 1 - 4 -2x >= -3Divide by -2: Now, we divide both sides by -2 to solve for x. Remember that dividing by a negative number reverses the inequality sign. -2x / -2 <= -3 / -2 x <= 3/2Find Integer Solutions: Since we are looking for integer values of x, we need to consider the integers that are less than or equal to 3/2. The only integers that satisfy this condition in the given interval 0 <= x <= 7 are 0 and 1.

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State all integer values of
x in the interval
0 <= x <= 7 that satisfy the following inequality:

-2x+4 >= 1
Answer:
x=

State all integer values of $x$ in the interval $0 \leq x \leq 7$ that satisfy the following inequality: $\newline$ $-2 x+4 \geq 1$ $\newline$ Answer: $x=$

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Algebra 2

Inverses of sin, cos, and tan: degrees

Full solution

Q. State all integer values of

x

in the interval

0 \leq x \leq 7

that satisfy the following inequality:

\newline

-2 x+4 \geq 1

\newline

Answer:

x=

Solve for x: First, we need to solve the inequality for $x$ . $-2x + 4 \geq 1$ Subtract $4$ from both sides to isolate the term containing $x$ . $-2x + 4 - 4 \geq 1 - 4$ $-2x \geq -3$
Divide by $-2$ : Now, we divide both sides by $-2$ to solve for $x$ . Remember that dividing by a negative number reverses the inequality sign. $\newline$ $-2x / -2 \leq -3 / -2$ $\newline$ $x \leq 3/2$
Find Integer Solutions: Since we are looking for integer values of $x$ , we need to consider the integers that are less than or equal to $\frac{3}{2}$ . The only integers that satisfy this condition in the given interval $0 \leq x \leq 7$ are $0$ and $1$ .