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Math Problems
Algebra 1
Find the inverse of a linear function
Put the following equation of a line into slope-intercept form, simplifying all fractions.
\newline
8
x
+
4
y
=
−
12
8 x+4 y=-12
8
x
+
4
y
=
−
12
\newline
Answer:
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Put the following equation of a line into slope-intercept form, simplifying all fractions.
\newline
8
y
−
10
x
=
−
56
8 y-10 x=-56
8
y
−
10
x
=
−
56
\newline
Answer:
Get tutor help
Put the following equation of a line into slope-intercept form, simplifying all fractions.
\newline
20
y
−
16
x
=
80
20 y-16 x=80
20
y
−
16
x
=
80
\newline
Answer:
Get tutor help
Put the following equation of a line into slope-intercept form, simplifying all fractions.
\newline
x
+
2
y
=
−
10
x+2 y=-10
x
+
2
y
=
−
10
\newline
Answer:
Get tutor help
Put the following equation of a line into slope-intercept form, simplifying all fractions.
\newline
y
−
x
=
6
y-x=6
y
−
x
=
6
\newline
Answer:
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Put the following equation of a line into slope-intercept form, simplifying all fractions.
\newline
3
x
+
9
y
=
−
36
3 x+9 y=-36
3
x
+
9
y
=
−
36
\newline
Answer:
Get tutor help
Put the following equation of a line into slope-intercept form, simplifying all fractions.
\newline
2
y
−
4
x
=
2
2 y-4 x=2
2
y
−
4
x
=
2
\newline
Answer:
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Put the following equation of a line into slope-intercept form, simplifying all fractions.
\newline
15
y
−
6
x
=
60
15 y-6 x=60
15
y
−
6
x
=
60
\newline
Answer:
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Put the following equation of a line into slope-intercept form, simplifying all fractions.
\newline
3
x
+
18
y
=
18
3 x+18 y=18
3
x
+
18
y
=
18
\newline
Answer:
Get tutor help
Put the following equation of a line into slope-intercept form, simplifying all fractions.
\newline
2
x
−
2
y
=
16
2 x-2 y=16
2
x
−
2
y
=
16
\newline
Answer:
Get tutor help
Put the following equation of a line into slope-intercept form, simplifying all fractions.
\newline
3
x
+
3
y
=
24
3 x+3 y=24
3
x
+
3
y
=
24
\newline
Answer:
Get tutor help
Put the following equation of a line into slope-intercept form, simplifying all fractions.
\newline
9
x
+
3
y
=
−
18
9 x+3 y=-18
9
x
+
3
y
=
−
18
\newline
Answer:
Get tutor help
Put the following equation of a line into slope-intercept form, simplifying all fractions.
\newline
2
x
+
4
y
=
−
16
2 x+4 y=-16
2
x
+
4
y
=
−
16
\newline
Answer:
Get tutor help
Put the following equation of a line into slope-intercept form, simplifying all fractions.
\newline
20
y
−
12
x
=
−
20
20 y-12 x=-20
20
y
−
12
x
=
−
20
\newline
Answer:
Get tutor help
Put the following equation of a line into slope-intercept form, simplifying all fractions.
\newline
5
x
−
3
y
=
12
5 x-3 y=12
5
x
−
3
y
=
12
\newline
Answer:
Get tutor help
Put the following equation of a line into slope-intercept form, simplifying all fractions.
\newline
3
x
−
2
y
=
−
14
3 x-2 y=-14
3
x
−
2
y
=
−
14
\newline
Answer:
Get tutor help
Put the following equation of a line into slope-intercept form, simplifying all fractions.
\newline
12
x
+
8
y
=
24
12 x+8 y=24
12
x
+
8
y
=
24
\newline
Answer:
Get tutor help
Put the following equation of a line into slope-intercept form, simplifying all fractions.
\newline
3
x
+
3
y
=
−
6
3 x+3 y=-6
3
x
+
3
y
=
−
6
\newline
Answer:
Get tutor help
Put the following equation of a line into slope-intercept form, simplifying all fractions.
\newline
x
+
4
y
=
−
12
x+4 y=-12
x
+
4
y
=
−
12
\newline
Answer:
Get tutor help
Express
z
1
=
−
5
5
−
5
15
i
z_{1}=-5 \sqrt{5}-5 \sqrt{15} i
z
1
=
−
5
5
−
5
15
i
in polar form.
\newline
Express your answer in exact terms, using radians, where your angle is between
0
0
0
and
2
π
2 \pi
2
π
radians, inclusive.
\newline
z
1
=
z_{1}=
z
1
=
Get tutor help
Express
z
1
=
−
14
+
14
i
z_{1}=-14+14 i
z
1
=
−
14
+
14
i
in polar form.
\newline
Express your answer in exact terms, using degrees, where your angle is between
0
∘
0^{\circ}
0
∘
and
36
0
∘
360^{\circ}
36
0
∘
, inclusive.
\newline
z
1
=
z_{1}=
z
1
=
Get tutor help
Express
z
1
=
−
10
3
−
10
i
z_{1}=-10 \sqrt{3}-10 i
z
1
=
−
10
3
−
10
i
in polar form.
\newline
Express your answer in exact terms, using radians, where your angle is between
0
0
0
and
2
π
2 \pi
2
π
radians, inclusive.
\newline
z
1
=
z_{1}=
z
1
=
Get tutor help
Express
z
1
=
3
3
−
9
i
z_{1}=3 \sqrt{3}-9 i
z
1
=
3
3
−
9
i
in polar form.
\newline
Express your answer in exact terms, using radians, where your angle is between
0
0
0
and
2
π
2 \pi
2
π
radians, inclusive.
\newline
z
1
=
z_{1}=
z
1
=
Get tutor help
Express
z
1
=
24
+
0
i
z_{1}=24+0 i
z
1
=
24
+
0
i
in polar form.
\newline
Express your answer in exact terms, using radians, where your angle is between
0
0
0
and
2
π
2 \pi
2
π
radians, inclusive.
\newline
z
1
=
z_{1}=
z
1
=
Get tutor help
Express
z
1
=
3
−
3
i
z_{1}=3-3 i
z
1
=
3
−
3
i
in polar form. Express your answer in exact terms, using radians, where your angle is between
0
0
0
and
2
π
2 \pi
2
π
radians, inclusive.
\newline
z
1
=
z_{1}=
z
1
=
Get tutor help
Express
z
1
=
0
+
10
i
z_{1}=0+10 i
z
1
=
0
+
10
i
in polar form.
\newline
Express your answer in exact terms, using degrees, where your angle is between
0
∘
0^{\circ}
0
∘
and
36
0
∘
360^{\circ}
36
0
∘
, inclusive.
\newline
z
1
=
z_{1}=
z
1
=
Get tutor help
Find the distance
d
d
d
between
z
1
=
(
8
+
3
i
)
z_{1}=(8+3 i)
z
1
=
(
8
+
3
i
)
and
z
2
=
(
5
−
7
i
)
z_{2}=(5-7 i)
z
2
=
(
5
−
7
i
)
. Express your answer in exact terms and simplify, if needed.
\newline
d
=
d=
d
=
Get tutor help
Find the distance
d
d
d
between
z
1
=
(
2
+
2
i
)
z_{1}=(2+2 i)
z
1
=
(
2
+
2
i
)
and
z
2
=
(
6
−
4
i
)
z_{2}=(6-4 i)
z
2
=
(
6
−
4
i
)
. Express your answer in exact terms and simplify, if needed.
\newline
d
=
d=
d
=
Get tutor help
Express
z
1
=
17
[
cos
(
π
)
+
i
sin
(
π
)
]
in
z_{1}=17[\cos (\pi)+i \sin (\pi)] \text { in }
z
1
=
17
[
cos
(
π
)
+
i
sin
(
π
)]
in
rectangular form.
\newline
Express your answer in exact terms.
\newline
z
1
=
z_{1}=
z
1
=
Get tutor help
g
(
x
)
=
3
x
−
5
g(x)=3 x-5
g
(
x
)
=
3
x
−
5
\newline
h
(
x
)
=
2
2
x
+
3
h(x)=\frac{2}{2 x+3}
h
(
x
)
=
2
x
+
3
2
\newline
Write
h
(
g
(
x
)
)
h(g(x))
h
(
g
(
x
))
as an expression in terms of
x
x
x
.
\newline
h
(
g
(
x
)
)
=
h(g(x))=
h
(
g
(
x
))
=
Get tutor help
f
(
x
)
=
6
x
−
4
f(x)=6 x-4
f
(
x
)
=
6
x
−
4
\newline
g
(
x
)
=
3
x
2
−
2
x
−
10
g(x)=3 x^{2}-2 x-10
g
(
x
)
=
3
x
2
−
2
x
−
10
\newline
Write
(
g
∘
f
)
(
x
)
(g \circ f)(x)
(
g
∘
f
)
(
x
)
as an expression in terms of
x
x
x
.
\newline
(
g
∘
f
)
(
x
)
=
(g \circ f)(x)=
(
g
∘
f
)
(
x
)
=
Get tutor help
The graph of a sinusoidal function has a minimum point at
(
0
,
2
)
(0,2)
(
0
,
2
)
and then has a maximum point at
(
3
π
,
6
)
(3 \pi, 6)
(
3
π
,
6
)
.
\newline
Write the formula of the function, where
x
x
x
is entered in radians.
\newline
f
(
x
)
=
□
f(x)=\square
f
(
x
)
=
□
Get tutor help
The graph of a sinusoidal function has a minimum point at
(
0
,
3
)
(0,3)
(
0
,
3
)
and then intersects its midline at
(
5
π
,
5
)
(5 \pi, 5)
(
5
π
,
5
)
.
\newline
Write the formula of the function, where
x
x
x
is entered in radians.
\newline
f
(
x
)
=
□
f(x)=\square
f
(
x
)
=
□
Get tutor help
The graph of a sinusoidal function has a minimum point at
(
0
,
−
3
)
(0,-3)
(
0
,
−
3
)
and then intersects its midline at
(
1
,
1
)
(1,1)
(
1
,
1
)
.
\newline
Write the formula of the function, where
x
x
x
is entered in radians.
\newline
f
(
x
)
=
f(x)=
f
(
x
)
=
Get tutor help
If
y
=
1.
8
x
+
1
y=1.8^{x}+1
y
=
1.
8
x
+
1
is graphed in the
x
y
x y
x
y
-plane, which of the following characteristics of the graph is displayed as a constant or coefficient in the equation?
\newline
Choose
1
1
1
answer:
\newline
(A)
y
y
y
-intercept
\newline
(B)
x
x
x
-intercept
\newline
(C) Slope
\newline
(D) The value
y
y
y
approaches as
x
x
x
decreases
Get tutor help
The polynomial
p
(
x
)
=
3
x
3
−
5
x
2
−
4
x
+
4
p(x)=3 x^{3}-5 x^{2}-4 x+4
p
(
x
)
=
3
x
3
−
5
x
2
−
4
x
+
4
has a known factor of
(
x
−
2
)
(x-2)
(
x
−
2
)
.
\newline
Rewrite
p
(
x
)
p(x)
p
(
x
)
as a product of linear factors.
\newline
p
(
x
)
=
p(x)=
p
(
x
)
=
Get tutor help
The polynomial
p
(
x
)
=
x
3
+
3
x
2
−
4
p(x)=x^{3}+3 x^{2}-4
p
(
x
)
=
x
3
+
3
x
2
−
4
has a known factor of
(
x
−
1
)
(x-1)
(
x
−
1
)
.
\newline
Rewrite
p
(
x
)
p(x)
p
(
x
)
as a product of linear factors.
\newline
p
(
x
)
=
p(x)=
p
(
x
)
=
Get tutor help
The polynomial
p
(
x
)
=
x
3
−
7
x
−
6
p(x)=x^{3}-7 x-6
p
(
x
)
=
x
3
−
7
x
−
6
has a known factor of
(
x
+
1
)
(x+1)
(
x
+
1
)
.
\newline
Rewrite
p
(
x
)
p(x)
p
(
x
)
as a product of linear factors.
\newline
p
(
x
)
=
p(x)=
p
(
x
)
=
Get tutor help
The polynomial
p
(
x
)
=
x
3
−
6
x
2
+
32
p(x)=x^{3}-6 x^{2}+32
p
(
x
)
=
x
3
−
6
x
2
+
32
has a known factor of
(
x
−
4
)
(x-4)
(
x
−
4
)
.
\newline
Rewrite
p
(
x
)
p(x)
p
(
x
)
as a product of linear factors.
\newline
p
(
x
)
=
p(x)=
p
(
x
)
=
Get tutor help
Divide the polynomials.
\newline
Your answer should be in the form
p
(
x
)
+
k
x
p(x)+\frac{k}{x}
p
(
x
)
+
x
k
where
p
p
p
is a polynomial and
k
k
k
is an integer.
\newline
6
x
2
−
4
x
−
3
x
=
□
\frac{6 x^{2}-4 x-3}{x}=\square
x
6
x
2
−
4
x
−
3
=
□
Get tutor help
Divide the polynomials.
\newline
Your answer should be in the form
p
(
x
)
+
k
x
p(x)+\frac{k}{x}
p
(
x
)
+
x
k
where
p
p
p
is a polynomial and
k
k
k
is an integer.
\newline
4
x
3
−
x
2
+
3
x
=
□
\frac{4 x^{3}-x^{2}+3}{x}=\square
x
4
x
3
−
x
2
+
3
=
□
Get tutor help
The polynomial
p
(
x
)
=
5
x
3
−
9
x
2
−
6
x
+
8
p(x)=5 x^{3}-9 x^{2}-6 x+8
p
(
x
)
=
5
x
3
−
9
x
2
−
6
x
+
8
has a known factor of
(
x
+
1
)
(x+1)
(
x
+
1
)
.
\newline
Rewrite
p
(
x
)
p(x)
p
(
x
)
as a product of linear factors.
\newline
p
(
x
)
=
p(x)=
p
(
x
)
=
Get tutor help
The polynomial
p
(
x
)
=
x
3
−
19
x
−
30
p(x)=x^{3}-19 x-30
p
(
x
)
=
x
3
−
19
x
−
30
has a known factor of
(
x
+
2
)
(x+2)
(
x
+
2
)
.
\newline
Rewrite
p
(
x
)
p(x)
p
(
x
)
as a product of linear factors.
\newline
p
(
x
)
=
p(x)=
p
(
x
)
=
Get tutor help
The polynomial
p
(
x
)
=
x
3
+
7
x
2
−
36
p(x)=x^{3}+7 x^{2}-36
p
(
x
)
=
x
3
+
7
x
2
−
36
has a known factor of
(
x
+
3
)
(x+3)
(
x
+
3
)
.
\newline
Rewrite
p
(
x
)
p(x)
p
(
x
)
as a product of linear factors.
\newline
p
(
x
)
=
p(x)=
p
(
x
)
=
Get tutor help
Divide the polynomials.
\newline
Your answer should be in the form
p
(
x
)
+
k
x
p(x)+\frac{k}{x}
p
(
x
)
+
x
k
where
p
p
p
is a polynomial and
k
k
k
is an integer.
\newline
2
x
4
+
5
x
+
4
x
=
□
\frac{2 x^{4}+5 x+4}{x}=\square
x
2
x
4
+
5
x
+
4
=
□
Get tutor help
For a given input value
x
x
x
, the function
h
h
h
outputs a value
y
y
y
to satisfy the following equation.
\newline
6
x
+
y
=
4
x
+
11
y
6x+y=4x+11y
6
x
+
y
=
4
x
+
11
y
\newline
Write a formula for
h
(
x
)
h(x)
h
(
x
)
in terms of
x
x
x
.
\newline
h
(
x
)
=
h(x)=
h
(
x
)
=
Get tutor help
For a given input value
n
n
n
, the function
g
g
g
outputs a value
m
m
m
to satisfy the following equation.
\newline
3
m
−
5
n
=
11
3m-5n=11
3
m
−
5
n
=
11
\newline
Write a formula for
g
(
n
)
g(n)
g
(
n
)
in terms of
n
n
n
.
\newline
g
(
n
)
=
□
g(n)=\square
g
(
n
)
=
□
Get tutor help
For a given input value
u
u
u
, the function
h
h
h
outputs a value
v
v
v
to satisfy the following equation.
\newline
4
u
+
8
v
=
−
3
u
+
2
v
4u + 8v = -3u + 2v
4
u
+
8
v
=
−
3
u
+
2
v
\newline
Write a formula for
h
(
u
)
h(u)
h
(
u
)
in terms of
u
u
u
.
\newline
h
(
u
)
=
h(u) =
h
(
u
)
=
Get tutor help
For a given input value
u
u
u
, the function
g
g
g
outputs a value
v
v
v
to satisfy the following equation.
\newline
−
12
u
+
3
=
8
v
+
1
-12u + 3 = 8v + 1
−
12
u
+
3
=
8
v
+
1
\newline
Write a formula for
g
(
u
)
g(u)
g
(
u
)
in terms of
u
u
u
.
\newline
g
(
u
)
=
g(u) =
g
(
u
)
=
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For a given input value
q
q
q
, the function
f
f
f
outputs a value
r
r
r
to satisfy the following equation.
\newline
11
q
−
4
=
3
r
−
6
11q - 4 = 3r - 6
11
q
−
4
=
3
r
−
6
\newline
Write a formula for
f
(
q
)
f(q)
f
(
q
)
in terms of
q
q
q
.
\newline
f
(
q
)
=
f(q) =
f
(
q
)
=
Get tutor help
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