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Express 
z_(1)=-10sqrt3-10 i in polar form.
Express your answer in exact terms, using radians, where your angle is between 0 and 
2pi radians, inclusive.

z_(1)=

Express z1=10310i z_{1}=-10 \sqrt{3}-10 i in polar form.\newlineExpress your answer in exact terms, using radians, where your angle is between 00 and 2π 2 \pi radians, inclusive.\newlinez1= z_{1}=

Full solution

Q. Express z1=10310i z_{1}=-10 \sqrt{3}-10 i in polar form.\newlineExpress your answer in exact terms, using radians, where your angle is between 00 and 2π 2 \pi radians, inclusive.\newlinez1= z_{1}=
  1. Calculate Magnitude: To express the complex number z1=10310i z_1 = -10\sqrt{3} - 10i in polar form, we need to find its magnitude (r) and angle (θ\theta) with respect to the positive x-axis. The magnitude is found using the formula r=a2+b2 r = \sqrt{a^2 + b^2} , where a a is the real part and b b is the imaginary part of the complex number.\newlineCalculation: r=(103)2+(10)2=300+100=400=20 r = \sqrt{(-10\sqrt{3})^2 + (-10)^2} = \sqrt{300 + 100} = \sqrt{400} = 20 .
  2. Calculate Angle: Next, we find the angle θ\theta using the formula θ=arctan(ba) \theta = \arctan\left(\frac{b}{a}\right) , where a a is the real part and b b is the imaginary part of the complex number. Since the complex number is in the third quadrant (both real and imaginary parts are negative), we need to add π\pi to the angle obtained from the arctan function to get the angle in the correct quadrant.\newlineCalculation: θ=arctan(10103)=arctan(13) \theta = \arctan\left(\frac{-10}{-10\sqrt{3}}\right) = \arctan\left(\frac{1}{\sqrt{3}}\right) . The arctan of 13 \frac{1}{\sqrt{3}} is π6 \frac{\pi}{6} , but since the complex number is in the third quadrant, we add π\pi to get θ=π6+π=7π6 \theta = \frac{\pi}{6} + \pi = \frac{7\pi}{6} .
  3. Find Polar Form: The polar form of a complex number is given by r(cos(θ)+isin(θ)) r(\cos(\theta) + i\sin(\theta)) . Substituting the values of r r and θ \theta we found in the previous steps, we get the polar form of z1 z_1 .\newlineCalculation: z1=20(cos(7π6)+isin(7π6)) z_1 = 20(\cos(\frac{7\pi}{6}) + i\sin(\frac{7\pi}{6})) .

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