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For a given input value x, the function h outputs a value y to satisfy the following equation. 6x+y=4x+11 y Write a formula for h(x) in terms of x. h(x)=

For a given input value xx, the function hh outputs a value yy to satisfy the following equation.\newline6x+y=4x+11y6x+y=4x+11y\newlineWrite a formula for h(x)h(x) in terms of xx.\newlineh(x)=h(x)=

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Q. For a given input value xx, the function hh outputs a value yy to satisfy the following equation.\newline6x+y=4x+11y6x+y=4x+11y\newlineWrite a formula for h(x)h(x) in terms of xx.\newlineh(x)=h(x)=
  1. Isolate y: First, we need to isolate y on one side of the equation to find a formula for h(x) in terms of x. The given equation is 6x+y=4x+11y6x + y = 4x + 11y.
  2. Subtract 4x4x: Subtract 4x4x from both sides of the equation to start isolating yy.\newline6x+y−4x=4x+11y−4x6x + y - 4x = 4x + 11y - 4x\newlineThis simplifies to 2x+y=11y2x + y = 11y.
  3. Subtract yy: Now, subtract yy from both sides to get all the yy terms on one side.\newline2x+y−y=11y−y2x + y - y = 11y - y\newlineThis simplifies to 2x=10y2x = 10y.
  4. Divide by 1010: To solve for yy, divide both sides by 1010.y=2x10y = \frac{2x}{10}Simplify the fraction by dividing both the numerator and the denominator by 22.y=x5y = \frac{x}{5}
  5. Write h(x)h(x): Now that we have isolated yy, we can write the function h(x)h(x) in terms of xx.h(x)=x5h(x) = \frac{x}{5}

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