Divide the polynomials. Your answer should be in the form p(x)+(k)/(x) where p is a polynomial and k is an integer. (6x^(2)-4x-3)/(x)=◻

Divide by x: Now, divide the second term by x. (-4x)/x = -4, because x/x is 1, and -4 times 1 is -4.Divide second term: Finally, divide the constant term by x. (-3)/x remains as it is because we can't simplify it further without knowing the value of x.Divide constant term: Putting it all together, we get the polynomial part and the remainder. So, the answer is 6x - 4 with a remainder of -3/x.

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Divide the polynomials.
Your answer should be in the form
p(x)+(k)/(x) where
p is a polynomial and
k is an integer.

(6x^(2)-4x-3)/(x)=◻

Divide the polynomials. $\newline$ Your answer should be in the form $p(x)+\frac{k}{x}$ where $p$ is a polynomial and $k$ is an integer. $\newline$ $\frac{6 x^{2}-4 x-3}{x}=\square$

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Math Problems

Algebra 1

Find the inverse of a linear function

Full solution

Q. Divide the polynomials.

\newline

Your answer should be in the form

p(x)+\frac{k}{x}

where

p

is a polynomial and

k

is an integer.

\newline

\frac{6 x^{2}-4 x-3}{x}=\square

Divide by $x$ : Now, divide the second term by $x$ . $\frac{-4x}{x} = -4$ , because $\frac{x}{x} = 1$ , and $-4 \times 1 = -4$ .
Divide second term: Finally, divide the constant term by $x$ . $\frac{-3}{x}$ remains as it is because we can't simplify it further without knowing the value of $x$ .
Divide constant term: Putting it all together, we get the polynomial part and the remainder. $\newline$ So, the answer is $6x - 4$ with a remainder of $-\frac{3}{x}$ .