Q. For a given input value u, the function g outputs a value v to satisfy the following equation.−12u+3=8v+1Write a formula for g(u) in terms of u.g(u)=
Write equation: Write down the given equation.The given equation is −12u+3=8v+1.
Isolate term: Isolate the term with on one side of the equation.To do this, we subtract from both sides of the equation to get −12-12−12u + 222 = 888v.
Divide by 888: Divide both sides of the equation by 888 to solve for vvv.\newlineDoing this, we get −12u+28=v\frac{{-12u + 2}}{{8}} = v8−12u+2=v.
Simplify equation: Simplify the equation.\newlineWe can simplify the fraction by dividing both the numerator terms by 888. This gives us −128u+28=v\frac{-12}{8}u + \frac{2}{8} = v8−12u+82=v.
Further simplify coefficients: Further simplify the coefficients in the equation.\newline−128-\frac{12}{8}−812 simplifies to −32-\frac{3}{2}−23, and 28\frac{2}{8}82 simplifies to 14\frac{1}{4}41. So, we have (−32)u+14=v(-\frac{3}{2})u + \frac{1}{4} = v(−23)u+41=v.
Write function g(u) g(u) g(u): Write the function g(u) g(u) g(u) in terms of u u u.\newlineSince v v v is the output of the function g g g when the input is u u u, we can write g(u)=(−32)u+14 g(u) = \left(-\frac{3}{2}\right)u + \frac{1}{4} g(u)=(−23)u+41.
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