Divide the polynomials. Your answer should be in the form p(x)+(k)/(x) where p is a polynomial and k is an integer. (4x^(3)-x^(2)+3)/(x)=◻

Divide by x: Divide each term of the polynomial $4x^3 - x^2 + 3$ by $x$. We divide $4x^3$ by $x$ to get $4x^2$. We divide $-x^2$ by $x$ to get $-x$. We divide $3$ by $x$ to get $\frac{3}{x}$.Combine the results: Combine the results of the division to form the final expression. The polynomial part $p(x)$ is $4x^2 - x$. The remainder is $\frac{3}{x}$. So, the final expression is $4x^2 - x + \frac{3}{x}$.

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Divide the polynomials.
Your answer should be in the form
p(x)+(k)/(x) where
p is a polynomial and
k is an integer.

(4x^(3)-x^(2)+3)/(x)=◻

Divide the polynomials. $\newline$ Your answer should be in the form $p(x)+\frac{k}{x}$ where $p$ is a polynomial and $k$ is an integer. $\newline$ $\frac{4 x^{3}-x^{2}+3}{x}=\square$

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Math Problems

Algebra 1

Find the inverse of a linear function

Full solution

Q. Divide the polynomials.

\newline

Your answer should be in the form

p(x)+\frac{k}{x}

where

p

is a polynomial and

k

is an integer.

\newline

\frac{4 x^{3}-x^{2}+3}{x}=\square

Divide by x: Divide each term of the polynomial $4x^3 - x^2 + 3$ by $x$ . $\newline$ We divide $4x^3$ by $x$ to get $4x^2$ . $\newline$ We divide $-x^2$ by $x$ to get $-x$ . $\newline$ We divide $3$ by $x$ to get $x$ $0$ .
Combine the results: Combine the results of the division to form the final expression. $\newline$ The polynomial part $p(x)$ is $4x^2 - x$ . $\newline$ The remainder is $\frac{3}{x}$ . $\newline$ So, the final expression is $4x^2 - x + \frac{3}{x}$ .