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Math Problems
Grade 8
Solve multi-step equations with fractional coefficients
Solve the equation
2
x
−
3
4
+
5
=
3
x
\frac{2 x-3}{4}+5=3 x
4
2
x
−
3
+
5
=
3
x
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10
p
−
3
=
2
(
12
+
4
p
)
−
7
10p-3=2(12+4p)-7
10
p
−
3
=
2
(
12
+
4
p
)
−
7
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Solve. Show your work.
\newline
1
4
(
12
−
8
x
)
=
4
(
−
2
x
−
6
)
\frac{1}{4}(12-8 x)=4(-2 x-6)
4
1
(
12
−
8
x
)
=
4
(
−
2
x
−
6
)
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Simplify:
x
(
1
x
x
3
)
−
x
x
−
2
x
=
0
x(\frac{1}{x\sqrt{x^3}})-x^x-\frac{2}{x}=0\
x
(
x
x
3
1
)
−
x
x
−
x
2
=
0
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Solve for
k
k
k
.
\newline
8
(
3
4
k
+
3
)
=
8
−
2
k
8\left(\frac{3}{4}k + 3\right) = 8 - 2k
8
(
4
3
k
+
3
)
=
8
−
2
k
\newline
k
=
k =
k
=
__
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Solve for
s
s
s
.
\newline
9
(
2
3
s
−
1
)
=
−
2
s
9\left(\frac{2}{3}s - 1\right) = -2s
9
(
3
2
s
−
1
)
=
−
2
s
\newline
s
=
s =
s
=
__
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Solve for
r
r
r
.
\newline
r
=
4
(
1
5
r
+
2
)
r = 4\left(\frac{1}{5}r + 2\right)
r
=
4
(
5
1
r
+
2
)
\newline
r = ____
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Solve for
v
v
v
.
\newline
2
(
3
−
1
4
v
)
=
2
−
v
2(3 - \frac{1}{4}v) = 2 - v
2
(
3
−
4
1
v
)
=
2
−
v
\newline
v = ____
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Solve for
d
d
d
.
\newline
1
2
(
d
+
4
)
=
d
−
1
\frac{1}{2}(d + 4) = d - 1
2
1
(
d
+
4
)
=
d
−
1
\newline
d = ____
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Solve for
a
a
a
.
\newline
3
(
2
3
a
−
1
3
)
=
5
a
+
3
3\left(\frac{2}{3}a - \frac{1}{3}\right) = 5a + 3
3
(
3
2
a
−
3
1
)
=
5
a
+
3
\newline
a = ____
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Solve for
y
y
y
.
\newline
−
2
+
y
=
2
(
1
3
y
−
3
)
-2 + y = 2(\frac{1}{3}y - 3)
−
2
+
y
=
2
(
3
1
y
−
3
)
\newline
y
=
y =
y
=
__
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Solve for
v
v
v
.
\newline
v
−
5
=
1
2
(
v
+
10
)
v - 5 = \frac{1}{2}(v + 10)
v
−
5
=
2
1
(
v
+
10
)
\newline
v
=
v =
v
=
__
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Solve for
j
j
j
.
\newline
4
j
−
2
=
3
(
1
3
j
+
2
)
4j - 2 = 3\left(\frac{1}{3}j + 2\right)
4
j
−
2
=
3
(
3
1
j
+
2
)
\newline
j
=
j =
j
=
__
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Solve for
h
h
h
.
\newline
7
−
h
=
3
(
2
3
h
+
4
)
7 - h = 3\left(\frac{2}{3}h + 4\right)
7
−
h
=
3
(
3
2
h
+
4
)
\newline
h
=
h =
h
=
__
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Solve for
z
z
z
.
\newline
−
3
+
z
=
4
(
1
5
z
−
3
)
-3 + z = 4(\frac{1}{5}z - 3)
−
3
+
z
=
4
(
5
1
z
−
3
)
\newline
z
=
z =
z
=
__
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Solve for
b
b
b
.
\newline
b
+
3
=
1
2
(
b
−
4
)
b + 3 = \frac{1}{2}(b - 4)
b
+
3
=
2
1
(
b
−
4
)
\newline
b = ____
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Solve for
s
s
s
.
\newline
−
s
=
4
(
1
2
s
+
4
)
-s = 4(\frac{1}{2}s + 4)
−
s
=
4
(
2
1
s
+
4
)
\newline
s
=
s =
s
=
__
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Solve for
m
m
m
.
\newline
1
4
(
8
m
+
24
)
=
21
−
13
m
\frac{1}{4}(8m + 24) = 21 - 13m
4
1
(
8
m
+
24
)
=
21
−
13
m
\newline
m
=
m =
m
=
__
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Solve for
q
q
q
.
\newline
3
(
1
4
q
+
1
)
=
q
3\left(\frac{1}{4}q + 1\right) = q
3
(
4
1
q
+
1
)
=
q
\newline
q = ____
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Solve for
t
t
t
.
\newline
3
(
1
3
t
+
2
3
)
=
4
t
−
2
3\left(\frac{1}{3}t + \frac{2}{3}\right) = 4t - 2
3
(
3
1
t
+
3
2
)
=
4
t
−
2
\newline
t
=
t =
t
=
__
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Solve for
p
p
p
.
\newline
5
p
=
4
(
1
2
p
−
1
)
5p = 4\left(\frac{1}{2}p - 1\right)
5
p
=
4
(
2
1
p
−
1
)
\newline
p
=
p =
p
=
__
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Solve for
m
m
m
.
\newline
4
m
+
2
=
4
(
1
2
m
−
1
4
)
4m + 2 = 4\left(\frac{1}{2}m - \frac{1}{4}\right)
4
m
+
2
=
4
(
2
1
m
−
4
1
)
\newline
m
=
m =
m
=
__
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Solve for
x
x
x
.
\newline
2
−
x
=
2
(
3
−
1
4
x
)
2 - x = 2(3 - \frac{1}{4}x)
2
−
x
=
2
(
3
−
4
1
x
)
\newline
x
=
x =
x
=
__
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Solve for
c
c
c
.
\newline
1
2
c
=
2
(
1
2
c
−
3
)
\frac{1}{2}c = 2\left(\frac{1}{2}c - 3\right)
2
1
c
=
2
(
2
1
c
−
3
)
\newline
c = ____
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Solve for
j
j
j
.
\newline
5
(
4
5
j
+
2
)
=
3
−
6
j
5\left(\frac{4}{5}j + 2\right) = 3 - 6j
5
(
5
4
j
+
2
)
=
3
−
6
j
\newline
j
=
j =
j
=
__
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Solve for
b
b
b
.
\newline
b
+
1
=
1
4
(
3
b
+
2
)
b + 1 = \frac{1}{4}(3b + 2)
b
+
1
=
4
1
(
3
b
+
2
)
\newline
b
=
b =
b
=
__
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Solve for
v
v
v
.
\newline
1
2
v
+
8
=
3
−
1
3
v
\frac{1}{2}v + 8 = 3 - \frac{1}{3}v
2
1
v
+
8
=
3
−
3
1
v
\newline
v
=
v =
v
=
__
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Solve for
v
v
v
.
\newline
5
v
−
1
2
=
4
+
3
2
v
5v - \frac{1}{2} = 4 + \frac{3}{2}v
5
v
−
2
1
=
4
+
2
3
v
\newline
v
=
v =
v
=
__
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Solve.
\newline
2
x
+
8
5
=
3
x
+
2
6
\frac{2 x+8}{5}=\frac{3 x+2}{6}
5
2
x
+
8
=
6
3
x
+
2
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Solve the equation
2
x
+
7
3
=
2
−
x
4
\frac{2 x+7}{3}=\frac{2-x}{4}
3
2
x
+
7
=
4
2
−
x
.
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Find the solution to this equation.
\newline
−
x
+
2
(
x
+
3
)
=
6
+
x
-x+2(x+3)=6+x
−
x
+
2
(
x
+
3
)
=
6
+
x
\newline
(A) No solution
\newline
(B) All real numbers
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2
x
(
2
x
−
3
)
≥
4
x
2
−
3
(
2
x
+
1
)
2 x(2 x-3) \geq 4 x^{2}-3(2 x+1)
2
x
(
2
x
−
3
)
≥
4
x
2
−
3
(
2
x
+
1
)
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7
3
(
1
2
x
−
10
3
)
=
−
35
3
−
1
2
x
\frac{7}{3}(\frac{1}{2}x - \frac{10}{3}) = \frac{-35}{3} - \frac{1}{2}x
3
7
(
2
1
x
−
3
10
)
=
3
−
35
−
2
1
x
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if
(
3
y
−
5
x
)
/
(
7
x
−
4
y
)
=
3
/
4
(3y -5x)/(7x-4y) = 3/4
(
3
y
−
5
x
)
/
(
7
x
−
4
y
)
=
3/4
, find the value of
x
/
y
x/y
x
/
y
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Solve for
b
b
b
. Express your answer as a proper or improper fraction in simplest terms.
\newline
−
7
8
−
1
8
b
=
−
1
2
-\frac{7}{8}-\frac{1}{8} b=-\frac{1}{2}
−
8
7
−
8
1
b
=
−
2
1
\newline
Answer:
b
=
b=
b
=
Get tutor help
Solve for
x
x
x
. Express your answer as a proper or improper fraction in simplest terms.
\newline
−
1
4
=
1
5
x
+
1
4
-\frac{1}{4}=\frac{1}{5} x+\frac{1}{4}
−
4
1
=
5
1
x
+
4
1
\newline
Answer:
x
=
x=
x
=
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Solve for
m
m
m
.
\newline
4
+
5
m
=
9
m
\sqrt{4 + 5m} = \sqrt{9m}
4
+
5
m
=
9
m
\newline
m
=
m =
m
=
_____
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Simplify.
7
x
−
8
=
3
x
\frac{7}{x}-8=\frac{3}{x}
x
7
−
8
=
x
3
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3
z
−
4
y
=
2
z
−
4.5
3z-4y=2z-4.5
3
z
−
4
y
=
2
z
−
4.5
8
y
=
2
z
+
5
8y=2z+5
8
y
=
2
z
+
5
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solve and find
(
x
+
10
)
(
x
+
10
)
(x+10)(x+10)
(
x
+
10
)
(
x
+
10
)
3
x
−
7
=
11
3x-7=11
3
x
−
7
=
11
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Solve for
a
a
a
.
\newline
4
5
a
−
8
=
a
+
2
\frac{4}{5}a - 8 = a + 2
5
4
a
−
8
=
a
+
2
\newline
a
=
a =
a
=
__
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2
x
+
3
y
=
2
;
4
x
−
9
y
=
−
1
,
x
,
y
>
0
\frac{2}{\sqrt{x}}+\frac{3}{\sqrt{y}}=2 ; \frac{4}{\sqrt{x}}-\frac{9}{\sqrt{y}}=-1, \mathrm{x}, \mathrm{y}>0
x
2
+
y
3
=
2
;
x
4
−
y
9
=
−
1
,
x
,
y
>
0
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log
2
(
4
x
−
3
)
+
log
2
(
3
x
+
5
)
=
3
\log_{2}(4x-3)+\log_{2}(3x+5)=3
lo
g
2
(
4
x
−
3
)
+
lo
g
2
(
3
x
+
5
)
=
3
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Solve the equation:
2
(
x
2
+
x
−
11
)
3
2
=
54
2(x^{2}+x-11)^{\frac{3}{2}}=54
2
(
x
2
+
x
−
11
)
2
3
=
54
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Find the difference.
\newline
x
2
−
5
x
2
+
5
x
−
14
−
x
+
3
x
+
7
=
\frac{x^{2}-5}{x^{2}+5 x-14}-\frac{x+3}{x+7}=
x
2
+
5
x
−
14
x
2
−
5
−
x
+
7
x
+
3
=
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Solve for
x
x
x
.
\newline
x
+
7
6
x
+
2
=
2
x
−
1
x
\frac{x+7}{6 x}+2=\frac{2 x-1}{x}
6
x
x
+
7
+
2
=
x
2
x
−
1
\newline
Answer:
x
=
x=
x
=
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Solve for
x
x
x
.
\newline
−
5
3
−
4
3
x
=
−
2
\frac{-5}{3}-\frac{4}{3 x}=-2
3
−
5
−
3
x
4
=
−
2
\newline
Answer:
x
=
x=
x
=
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Solve for
x
\mathrm{x}
x
:
\newline
8
x
−
24
−
15
=
−
11
\sqrt{8 x-24}-15=-11
8
x
−
24
−
15
=
−
11
\newline
Answer:
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Solve the equation
x
2
−
4
x
+
38
=
8
x
+
4
x^{2}-4 x+38=8 x+4
x
2
−
4
x
+
38
=
8
x
+
4
to the nearest tenth.
\newline
Answer:
x
=
x=
x
=
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Solve for all values of
x
x
x
.
\newline
x
−
7
x
+
8
=
3
x
\frac{x-7}{x+8}=\frac{3}{x}
x
+
8
x
−
7
=
x
3
\newline
Answer:
x
=
x=
x
=
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2
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