Solve for x : sqrt(8x-24)-15=-11 Answer:

Isolate square root term: First, isolate the square root term on one side of the equation. sqrt(8x-24) - 15 = -11 Add 15 to both sides to isolate the square root. sqrt(8x-24) - 15 + 15 = -11 + 15 sqrt(8x-24) = 4Square both sides: Next, square both sides of the equation to eliminate the square root. (sqrt(8x-24))^2 = 4^2 8x - 24 = 16Isolate variable term: Now, isolate the variable term by adding 24 to both sides of the equation. 8x - 24 + 24 = 16 + 24 8x = 40Divide to solve for x: Finally, divide both sides by 8 to solve for x. 8x / 8 = 40 / 8 x = 5

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Math Problems

Grade 8

Solve multi-step equations with fractional coefficients

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Q. Solve for

\mathrm{x}

\newline

\sqrt{8 x-24}-15=-11

\newline

Answer:

Isolate square root term: First, isolate the square root term on one side of the equation. $\newline$ $\sqrt{8x-24} - 15 = -11$ $\newline$ Add $15$ to both sides to isolate the square root. $\newline$ $\sqrt{8x-24} - 15 + 15 = -11 + 15$ $\newline$ $\sqrt{8x-24} = 4$
Square both sides: Next, square both sides of the equation to eliminate the square root. $\newline$ $(\sqrt{8x-24})^2 = 4^2$ $\newline$ $8x - 24 = 16$
Isolate variable term: Now, isolate the variable term by adding $24$ to both sides of the equation. $\newline$ $8x - 24 + 24 = 16 + 24$ $\newline$ $8x = 40$
Divide to solve for x: Finally, divide both sides by $8$ to solve for $x$ . $\newline$ $\frac{8x}{8} = \frac{40}{8}$ $\newline$ $x = 5$