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Solve for zz.\newline3+z=4(15z3)-3 + z = 4(\frac{1}{5}z - 3)\newlinez=z = __

Full solution

Q. Solve for zz.\newline3+z=4(15z3)-3 + z = 4(\frac{1}{5}z - 3)\newlinez=z = __
  1. Distribute and Simplify: Distribute the 44 on the right side of the equation.3+z=4×(15z3)-3 + z = 4 \times \left(\frac{1}{5}z - 3\right)=45z12= \frac{4}{5}z - 12
  2. Isolate z Terms: Add 33 to both sides to isolate the z terms.\newline3+z+3=45z12+3-3 + z + 3 = \frac{4}{5}z - 12 + 3\newlinez=45z9z = \frac{4}{5}z - 9
  3. Combine and Solve: Subtract 45z\frac{4}{5}z from both sides to get all zz terms on one side.\newlinez45z=9z - \frac{4}{5}z = -9\newline15z=9\frac{1}{5}z = -9