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Solve for qq.\newline3(14q+1)=q3\left(\frac{1}{4}q + 1\right) = q\newlineq = ____

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Q. Solve for qq.\newline3(14q+1)=q3\left(\frac{1}{4}q + 1\right) = q\newlineq = ____
  1. Distribute Terms: Distribute 33 to each term inside the parentheses.\newline3×(14q+1)=3×14q+3×13 \times (\frac{1}{4}q + 1) = 3 \times \frac{1}{4}q + 3 \times 1\newline=34q+3= \frac{3}{4}q + 3
  2. Isolate q: Rewrite the equation to isolate q on one side.\newline34q+3=q\frac{3}{4}q + 3 = q\newline34q+33=q3\frac{3}{4}q + 3 - 3 = q - 3 (subtracting 33 from both sides)\newline34q=q3\frac{3}{4}q = q - 3
  3. Subtract qq: Subtract qq from both sides to isolate terms with qq on one side.\newline34qq=q3q\frac{3}{4}q - q = q - 3 - q\newline34qq=3\frac{3}{4}q - q = -3
  4. Combine Like Terms: Combine like terms.\newline34q44q=3\frac{3}{4}q - \frac{4}{4}q = -3\newline14q=3-\frac{1}{4}q = -3
  5. Solve for q: Solve for q by multiplying both sides by -4").\(\newline\$-\frac{1}{4}q \times -4 = -3 \times -4\)\(\newline\)\(q = 12\)