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10p3=2(12+4p)710p-3=2(12+4p)-7

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Q. 10p3=2(12+4p)710p-3=2(12+4p)-7
  1. Distribute 22: Distribute 22 into the parentheses on the right side of the equation.\newline10p3=2×12+2×4p710p - 3 = 2 \times 12 + 2 \times 4p - 7\newline10p3=24+8p710p - 3 = 24 + 8p - 7
  2. Simplify right side: Simplify the right side by combining like terms. 10p3=17+8p10p - 3 = 17 + 8p
  3. Subtract 8p8p: Subtract 8p8p from both sides to start isolating pp.\newline10p8p3=17+8p8p10p - 8p - 3 = 17 + 8p - 8p\newline2p3=172p - 3 = 17
  4. Add 33: Add 33 to both sides to further isolate pp.\newline2p3+3=17+32p - 3 + 3 = 17 + 3\newline2p=202p = 20
  5. Divide by 22: Divide both sides by 22 to solve for pp.2p2=202\frac{2p}{2} = \frac{20}{2}p=10p = 10