Let h be a twice differentiable function, and let h(6)=7, h′(6)=0, and h′′(6)=0.What occurs in the graph of h at the point (6,7) ?Choose 1 answer:(A) (6,7) is a minimum point.(B) (6,7) is a maximum point.(C) There's not enough information to tell.
Q. Let h be a twice differentiable function, and let h(6)=7, h′(6)=0, and h′′(6)=0.What occurs in the graph of h at the point (6,7) ?Choose 1 answer:(A) (6,7) is a minimum point.(B) (6,7) is a maximum point.(C) There's not enough information to tell.
Analyze Given Information: To determine what occurs at the point (6,7) on the graph of h, we need to analyze the given information about the function and its derivatives at x=6.Given: h(6)=7, h′(6)=0, and h′′(6)=0.The value h(6)=7 simply gives us the point on the graph, which is (6,7).The first derivative h′(6)=0 indicates that the slope of the tangent line to the graph of h at x=6 is zero. This means that the graph has a horizontal tangent at this point, which could be a minimum, maximum, or a point of inflection.The second derivative h′′(6)=0 provides information about the concavity of the graph at x=6. Since the second derivative is zero, we cannot determine whether the graph is concave up or concave down at this point.
Interpret First Derivative: To determine whether (6,7) is a minimum or maximum point, or if there's not enough information, we would typically look at the sign of the second derivative. If h''(6) > 0, the graph would be concave up, and (6,7) would be a minimum point. If h''(6) < 0, the graph would be concave down, and (6,7) would be a maximum point.However, since h′′(6)=0, we cannot conclude whether the graph is concave up or down at that point. Therefore, we do not have enough information to determine if (6,7) is a minimum or maximum point.