Is the following function even, odd, or neither? f(x)=(1)/(4-x^(2)) Choose 1 answer: (A) Even (B) Odd (c) Neither

Define function and find f(-x): Define the function f(x) and find f(-x). The function given is f(x)=(1)/(4-x^(2)). To determine if the function is even, odd, or neither, we need to evaluate f(-x) and compare it to f(x). Substitute -x for x in f(x) to get f(-x). f(-x)=(1)/(4-(-x)^(2))Simplify f(-x): Simplify f(-x). Simplify the expression inside the parentheses. f(-x)=(1)/(4-((-x)^2)) Since (-x)^2 = x^2, we have: f(-x)=(1)/(4-x^2)Compare f(x) and f(-x): Compare f(x) and f(-x). We have f(x)=(1)/(4-x^2) and f(-x)=(1)/(4-x^2). Since f(-x) = f(x), the function f(x) is an even function.

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Is the following function even, odd, or neither?

f(x)=(1)/(4-x^(2))
Choose 1 answer:
(A) Even
(B) Odd
(c) Neither

Is the following function even, odd, or neither? $\newline$ $f(x)=\frac{1}{4-x^{2}}$ $\newline$ Choose $1$ answer: $\newline$ (A) Even $\newline$ (B) Odd $\newline$ (C) Neither

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Algebra 2

Even and odd functions

Full solution

Q. Is the following function even, odd, or neither?

\newline

f(x)=\frac{1}{4-x^{2}}

\newline

Choose

1

answer:

\newline

(A) Even

\newline

(B) Odd

\newline

Define function and find f(-x): Define the function f(x) and find f(-x). $\newline$ The function given is $f(x)=\frac{1}{4-x^{2}}$ . To determine if the function is even, odd, or neither, we need to evaluate $f(-x)$ and compare it to $f(x)$ . $\newline$ Substitute $-x$ for $x$ in $f(x)$ to get $f(-x)$ . $\newline$ $f(-x)=\frac{1}{4-(-x)^{2}}$
Simplify $f(-x)$ : Simplify $f(-x)$ . $\newline$ Simplify the expression inside the parentheses. $\newline$ $f(-x)=\frac{1}{4-((-x)^2)}$ $\newline$ Since $(-x)^2 = x^2$ , we have: $\newline$ $f(-x)=\frac{1}{4-x^2}$
Compare $f(x)$ and $f(-x)$ : Compare $f(x)$ and $f(-x)$ . $\newline$ We have $f(x)=\frac{1}{4-x^2}$ and $f(-x)=\frac{1}{4-(-x)^2}$ . $\newline$ Since $f(-x) = f(x)$ , the function $f(x)$ is an even function.