Solve for x. Enter the solutions from least to greatest. {:[(2x+4)(3x-2)=0],[" lesser "x=◻],[" greater "x=◻]:}

Factored Polynomial: Factored polynomial: (2x+4)(3x-2) Which equation finds the roots for this polynomial? Set the polynomial equal to zero. (2x+4)(3x-2) = 0Setting the Polynomial Equal to Zero: 2x + 4 = 0 What is the value of x? 2x + 4 = 0 2x = -4 x = -4 / 2 x = -2Solving for x in the First Equation: 3x - 2 = 0 What is the value of x? 3x - 2 = 0 3x = 2 x = 2 / 3 x = 2/3Solving for x in the Second Equation: We have found two roots: x = -2 x = 2/3 Now we need to write the roots from least to greatest. -2 is less than 2/3, so the order is correct.

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Solve for
x.
Enter the solutions from least to greatest.

{:[(2x+4)(3x-2)=0],[" lesser "x=◻],[" greater "x=◻]:}

Solve for $x$ . $\newline$ Enter the solutions from least to greatest. $\newline$ $(2 x+4)(3 x-2)=0$ $\newline$ lesser $x=$ $\newline$ greater $x=$

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Math Problems

Algebra 2

Find the roots of factored polynomials

Full solution

Q. Solve for

x

\newline

Enter the solutions from least to greatest.

\newline

(2 x+4)(3 x-2)=0

\newline

lesser

x=

\newline

greater

x=

Factored Polynomial: Factored polynomial: $(2x+4)(3x-2)$ $\newline$ Which equation finds the roots for this polynomial? $\newline$ Set the polynomial equal to zero. $\newline$ $(2x+4)(3x-2) = 0$
Setting the Polynomial Equal to Zero: $2x + 4 = 0$
What is the value of $x$ ?
$2x + 4 = 0$
$2x = -4$
$x = \frac{-4}{2}$
$x = -2$
Solving for x in the First Equation: $3x - 2 = 0$
What is the value of $x$ ?
$3x - 2 = 0$
$3x = 2$
$x = \frac{2}{3}$
$x = \frac{2}{3}$
Solving for x in the Second Equation: We have found two roots: $\newline$ x = $-2$ $\newline$ x = $\frac{2}{3}$ $\newline$ Now we need to write the roots from least to greatest. $\newline$ $-2$ is less than $\frac{2}{3}$ , so the order is correct.