Solve for x. Enter the solutions from least to greatest. {:[(x+6)(-x+1)=0],[" lesser "x=◻],[" greater "x=◻]:}

Factored Polynomial: Factored polynomial: (x + 6)(-x + 1) Which equation finds the roots for this polynomial? Set the polynomial equal to zero. (x + 6)(-x + 1) = 0First Root: First root: x + 6 = 0 What is the value of x? x + 6 = 0 x + 6 - 6 = 0 - 6 x = -6Second Root: Second root: -x + 1 = 0 What is the value of x? -x + 1 = 0 -x + 1 - 1 = 0 - 1 -x = -1 x = 1 (Multiplying both sides by -1)Ascending Order of Roots: We have found two roots: x = -6 x = 1 Now we need to write the roots in ascending order. Roots of the polynomial: -6, 1

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Solve for
x.
Enter the solutions from least to greatest.

{:[(x+6)(-x+1)=0],[" lesser "x=◻],[" greater "x=◻]:}

Solve for $x$ . $\newline$ Enter the solutions from least to greatest. $\newline$ $(x+6)(-x+1)=0$ $\newline$ lesser $x=$ $\newline$ greater $x=$

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Math Problems

Algebra 2

Find the roots of factored polynomials

Full solution

Q. Solve for

x

\newline

Enter the solutions from least to greatest.

\newline

(x+6)(-x+1)=0

\newline

lesser

x=

\newline

greater

x=

Factored Polynomial: Factored polynomial: $(x + 6)(-x + 1)$ $\newline$ Which equation finds the roots for this polynomial? $\newline$ Set the polynomial equal to zero. $\newline$ $(x + 6)(-x + 1) = 0$
First Root: First root: $x + 6 = 0$
What is the value of $x$ ?
$x + 6 = 0$
$x + 6 - 6 = 0 - 6$
$x = -6$
Second Root: Second root: $-x + 1 = 0$ $\newline$ What is the value of $x$ ? $\newline$ $-x + 1 = 0$ $\newline$ $-x + 1 - 1 = 0 - 1$ $\newline$ $-x = -1$ $\newline$ $x = 1$ (Multiplying both sides by $-1$ )
Ascending Order of Roots: We have found two roots: $\newline$ x = $-6$ $\newline$ x = $1$ $\newline$ Now we need to write the roots in ascending order. $\newline$ Roots of the polynomial: $-6$ , $1$