Solve for x. Enter the solutions from least to greatest. {:[(3x-6)(-x+3)=0],[" lesser "x=◻],[" greater "x=◻]:}

Factored equation: Factored equation: (3x-6)(-x+3)=0 To find the roots, set each factor equal to zero and solve for x.First factor: First factor: 3x - 6 = 0 Solve for x: 3x - 6 + 6 = 0 + 6 3x = 6 x = 6 / 3 x = 2Second factor: Second factor: -x + 3 = 0 Solve for x: -x + 3 - 3 = 0 - 3 -x = -3 Multiply both sides by -1 to get x: x = 3Solutions for x: We have found two solutions for x: x = 2 x = 3 Now we need to list them from least to greatest.Order of solutions: The least value is 2, and the greater value is 3. So the solutions in order from least to greatest are: lesser x = 2 greater x = 3

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Solve for
x.
Enter the solutions from least to greatest.

{:[(3x-6)(-x+3)=0],[" lesser "x=◻],[" greater "x=◻]:}

Solve for $x$ . $\newline$ Enter the solutions from least to greatest. $\newline$ $\begin{array}{l} (3 x-6)(-x+3)=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array}$

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Math Problems

Algebra 2

Find the roots of factored polynomials

Full solution

Q. Solve for

x

\newline

Enter the solutions from least to greatest.

\newline

\begin{array}{l} (3 x-6)(-x+3)=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array}

Factored equation: Factored equation: $(3x-6)(-x+3)=0$ $\newline$ To find the roots, set each factor equal to zero and solve for $x$ .
First factor: First factor: $3x - 6 = 0$
Solve for $x$ :
$3x - 6 + 6 = 0 + 6$
$3x = 6$
$x = \frac{6}{3}$
$x = 2$
Second factor: Second factor: $-x + 3 = 0$
Solve for $x$ :
$-x + 3 - 3 = 0 - 3$
$-x = -3$
Multiply both sides by $-1$ to get $x$ :
$x = 3$
Solutions for x: We have found two solutions for x: $\newline$ x = $2$ $\newline$ x = $3$ $\newline$ Now we need to list them from least to greatest.
Order of solutions: The least value is $2$ , and the greater value is $3$ . $\newline$ So the solutions in order from least to greatest are: $\newline$ lesser $x = 2$ $\newline$ greater $x = 3$