Q. Is the following function even, odd, or neither?f(x)=x2+23Choose 1 answer:(A) Even(B) Odd(C) Neither
Define function and f(−x): Define the function f(x) and determine f(−x). The function given is f(x)=x2+23. To determine if the function is even, odd, or neither, we need to evaluate f(−x) and compare it to f(x).
Substitute −x in f(x): Substitute −x for x in f(x) to find f(−x).f(−x)=(−x)2+23Since (−x)2 is equal to x2 (because the square of a negative number is positive), we can simplify f(−x) to:f(x)0
Compare f(x) and f(−x): Compare f(x) and f(−x). We have f(x)=x2+23 and f(−x)=x2+23. Since f(−x) is equal to f(x), the function f(x) is an even function.