Find the product. Simplify your answer. (3r - 1)(3r + 1) ______

Identify special case: Identify the special case for the product (3r - 1)(3r + 1). This product is in the form of (a - b)(a + b), which is a difference of squares. Special case: (a - b)(a + b) = a^2 - b^2Identify values of a and b: Identify the values of a and b. Compare (3r - 1)(3r + 1) with (a - b)(a + b). a = 3r b = 1Apply difference of squares formula: Apply the difference of squares formula to expand (3r - 1)(3r + 1). (a - b)(a + b) = a^2 - b^2 (3r - 1)(3r + 1) = (3r)^2 - (1)^2Simplify expression: Simplify (3r)^2 - (1)^2. (3r)^2 - (1)^2 = (3r * 3r) - (1 * 1) = 9r^2 - 1

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Find the product. Simplify your answer. $\newline$ $(3r - 1)(3r + 1)$

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Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(3r - 1)(3r + 1)

Identify special case: Identify the special case for the product $(3r - 1)(3r + 1)$ . This product is in the form of $(a - b)(a + b)$ , which is a difference of squares. Special case: $(a - b)(a + b) = a^2 - b^2$
Identify values of $a$ and $b$ : Identify the values of $a$ and $b$ . Compare $(3r - 1)(3r + 1)$ with $(a - b)(a + b)$ . $a = 3r$ $b = 1$
Apply difference of squares formula: Apply the difference of squares formula to expand $(3r - 1)(3r + 1)$ . $\newline$ $(a - b)(a + b) = a^2 - b^2$ $\newline$ $(3r - 1)(3r + 1) = (3r)^2 - (1)^2$
Simplify expression: Simplify $(3r)^2 - (1)^2.$ $(3r)^2 - (1)^2 = (3r \times 3r) - (1 \times 1)$ $= 9r^2 - 1$