Evaluate -6-(-6)+7+(-4)+(-1)". "

Evaluate Subtraction of Negative: We start by evaluating the expression -6-(-6)+7+(-4)+(-1). The first operation to consider is the subtraction of a negative number, which is the same as addition. -6 - (-6) = -6 + 6Add Numbers: Now we add the numbers -6 and 6 together. -6 + 6 = 0Add 7: Next, we add the result to the next number in the expression, which is 7. 0 + 7 = 7Add -4: We continue by adding the next number, which is -4. 7 + (-4) = 7 - 4Subtract 4: Now we subtract 4 from 7. 7 - 4 = 3Add -1: Finally, we add the last number in the expression, which is -1. 3 + (-1) = 3 - 1Subtract 1: We subtract 1 from 3 to get the final result. 3 - 1 = 2

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Evaluate $\newline$ $-6-(-6)+7+(-4)+(-1) \text {. }$

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Algebra 2

Add, subtract, multiply, and divide polynomials

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Q. Evaluate

\newline

-6-(-6)+7+(-4)+(-1) \text {. }

Evaluate Subtraction of Negative: We start by evaluating the expression $-6-(-6)+7+(-4)+(-1)$ . The first operation to consider is the subtraction of a negative number, which is the same as addition. $\newline$ $-6 - (-6) = -6 + 6$
Add Numbers: Now we add the numbers $-6$ and $6$ together. $-6 + 6 = 0$
Add $7$ : Next, we add the result to the next number in the expression, which is $7$ . $0 + 7 = 7$
Add $-4$ : We continue by adding the next number, which is $-4$ . $7 + (-4) = 7 - 4$
Subtract $4$ : Now we subtract $4$ from $7$ . $\newline$ $7 - 4 = 3$
Add $-1$ : Finally, we add the last number in the expression, which is $-1$ . $3 + (-1) = 3 - 1$
Subtract $1$ : We subtract $1$ from $3$ to get the final result. $\newline$ $3 - 1 = 2$