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Math Problems
Grade 8
Powers with negative bases
Evaluate.
\newline
(
−
1
)
2
=
(-1)^{2}=
(
−
1
)
2
=
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Evaluate.
\newline
(
−
5
2
)
2
=
\left(-\frac{5}{2}\right)^{2}=
(
−
2
5
)
2
=
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Evaluate.
\newline
(
−
3
2
)
4
=
\left(-\frac{3}{2}\right)^{4}=
(
−
2
3
)
4
=
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Evaluate.
\newline
(
−
3
4
)
2
=
\left(-\frac{3}{4}\right)^{2}=
(
−
4
3
)
2
=
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Evaluate.
\newline
(
−
5
3
)
2
=
\left(-\frac{5}{3}\right)^{2}=
(
−
3
5
)
2
=
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Evaluate.
\newline
(
−
1
2
)
5
=
\left(-\frac{1}{2}\right)^{5}=
(
−
2
1
)
5
=
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Evaluate.
\newline
(
−
3
4
)
3
=
\left(-\frac{3}{4}\right)^{3}=
(
−
4
3
)
3
=
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Evaluate.
\newline
(
−
3
1
3
)
2
=
\left(-3 \frac{1}{3}\right)^{2}=
(
−
3
3
1
)
2
=
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Evaluate.
\newline
(
−
1
3
)
3
=
\left(-\frac{1}{3}\right)^{3}=
(
−
3
1
)
3
=
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Evaluate.
\newline
(
−
4
1
2
)
2
=
\left(-4 \frac{1}{2}\right)^{2}=
(
−
4
2
1
)
2
=
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Evaluate.
\newline
−
2
2
=
-2^{2}=
−
2
2
=
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Evaluate.
\newline
−
4
3
=
-4^{3}=
−
4
3
=
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Evaluate.
\newline
(
−
2
1
2
)
2
=
\left(-2 \frac{1}{2}\right)^{2}=
(
−
2
2
1
)
2
=
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Subtract.
\newline
2
−
(
−
2
)
=
2-(-2)=
2
−
(
−
2
)
=
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Subtract.
\newline
4
−
(
−
4
)
=
4-(-4)=
4
−
(
−
4
)
=
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Subtract.
\newline
3
−
(
−
6
)
=
3-(-6)=
3
−
(
−
6
)
=
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Evaluate.
\newline
−
5
3
4
0
1
3
=
\frac{\sqrt[3]{-5}}{40^{\frac{1}{3}}}=
4
0
3
1
3
−
5
=
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Evaluate.
\newline
(
1
3
)
−
2
5
⋅
9
6
−
2
5
=
\left(\frac{1}{3}\right)^{-\frac{2}{5}} \cdot 96^{-\frac{2}{5}}=
(
3
1
)
−
5
2
⋅
9
6
−
5
2
=
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Evaluate.
\newline
12
5
−
11
12
12
5
−
1
4
=
\frac{125^{-\frac{11}{12}}}{125^{-\frac{1}{4}}}=
12
5
−
4
1
12
5
−
12
11
=
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lim
x
→
0
(
−
3
x
3
−
7
x
+
8
)
=
\lim _{x \rightarrow 0}\left(-3 x^{3}-7 x+8\right)=
lim
x
→
0
(
−
3
x
3
−
7
x
+
8
)
=
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Find the sum.
\newline
∑
k
=
1
40
(
5
k
−
87
)
=
\sum_{k=1}^{40}(5 k-87)=
k
=
1
∑
40
(
5
k
−
87
)
=
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∑
k
=
1
2
(
3
−
k
)
=
\sum_{k=1}^{2}(3-k)=
∑
k
=
1
2
(
3
−
k
)
=
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Evaluate the following expression.
\newline
8
+
8
1
4
=
8+\frac{8}{1^{4}}=
8
+
1
4
8
=
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Evaluate the following expression.
\newline
9
−
1
+
9
+
3
4
=
9-1+9+3^{4}=
9
−
1
+
9
+
3
4
=
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Evaluate the following expression.
\newline
2
⋅
1
0
4
−
7
3
=
2 \cdot 10^{4}-7^{3}=
2
⋅
1
0
4
−
7
3
=
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Evaluate the following expression.
\newline
4
⋅
6
÷
2
3
=
4 \cdot 6 \div 2^{3}=
4
⋅
6
÷
2
3
=
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Evaluate the following expression.
\newline
2
8
−
10
−
15
÷
3
=
2^{8}-10-15 \div 3=
2
8
−
10
−
15
÷
3
=
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Evaluate the following expression.
\newline
5
4
5
+
4
=
\frac{5^{4}}{5}+4=
5
5
4
+
4
=
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Evaluate the following expression.
\newline
6
⋅
2
+
6
4
=
6 \cdot 2+6^{4}=
6
⋅
2
+
6
4
=
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Evaluate the expression. Do not round your answer.
\newline
(
3
+
2
)
2
−
7
=
(3+2)^{2}-7=
(
3
+
2
)
2
−
7
=
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Evaluate the following expression.
\newline
1
0
7
+
9
+
1
3
=
10^{7}+9+1^{3}=
1
0
7
+
9
+
1
3
=
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Evaluate the following expression.
\newline
3
3
−
10
+
7
=
3^{3}-10+7=
3
3
−
10
+
7
=
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Evaluate the following expression.
\newline
10
+
5
3
−
1
=
10+5^{3}-1=
10
+
5
3
−
1
=
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Evaluate the following expression.
\newline
40
⋅
8
−
1
0
2
=
40 \cdot 8-10^{2}=
40
⋅
8
−
1
0
2
=
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Factor completely.
\newline
5
x
4
−
20
x
3
+
20
x
2
=
5 x^{4}-20 x^{3}+20 x^{2}=
5
x
4
−
20
x
3
+
20
x
2
=
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Factor completely.
\newline
3
x
5
−
75
x
3
=
3 x^{5}-75 x^{3}=
3
x
5
−
75
x
3
=
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Factor completely.
\newline
2
x
4
+
4
x
3
−
30
x
2
=
2 x^{4}+4 x^{3}-30 x^{2}=
2
x
4
+
4
x
3
−
30
x
2
=
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Factor completely.
\newline
7
x
5
−
21
x
4
+
14
x
3
=
7 x^{5}-21 x^{4}+14 x^{3}=
7
x
5
−
21
x
4
+
14
x
3
=
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Factor completely.
\newline
16
n
6
+
40
n
3
+
25
=
16 n^{6}+40 n^{3}+25=
16
n
6
+
40
n
3
+
25
=
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Factor completely.
\newline
4
p
2
−
25
q
2
=
4 p^{2}-25 q^{2}=
4
p
2
−
25
q
2
=
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6
4
3
+
3
6
4
3
=
4
⋅
6
A
\sqrt[3]{6^{4}}+3 \sqrt[3]{6^{4}}=4 \cdot 6^{A}
3
6
4
+
3
3
6
4
=
4
⋅
6
A
\newline
What is the value of
A
A
A
?
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Evaluate.
\newline
0.
1
3
=
0.1^{3}=
0.
1
3
=
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Evaluate.
\newline
0.
5
2
=
0.5^{2}=
0.
5
2
=
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Evaluate.
\newline
(
1
3
)
3
=
(\frac{1}{3})^{3}=
(
3
1
)
3
=
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Evaluate.
\newline
0.
2
4
=
0.2^{4}=
0.
2
4
=
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Evaluate.
\newline
0.
1
4
=
0.1^{4}=
0.
1
4
=
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Evaluate.
\newline
0.
7
2
=
0.7^{2}=
0.
7
2
=
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Evaluate.
\newline
(
4
7
)
2
=
(\frac{4}{7})^{2}=
(
7
4
)
2
=
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Evaluate.
\newline
(
2
5
)
2
=
(\frac{2}{5})^{2}=
(
5
2
)
2
=
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Evaluate.
\newline
0.
8
2
=
0.8^{2}=
0.
8
2
=
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