What is the constant term in the expression (1)/(12)(x-4)-(5)/(2)x(x^(2)-7x+1)?

Distribute and Combine Terms: Simplify the expression by distributing and combining like terms. (1/12)(x-4) - (5/2)x(x^2 - 7x + 1) = (1/12)x - (1/3) - (5/2)x^3 + (35/2)x^2 - (5/2)xCombine Like Terms: Combine like terms to simplify further. Combine the x terms and constant terms separately. = -(5/2)x^3 + (35/2)x^2 + ((1/12) - (5/2) - (1/3))x - 1/3 = -(5/2)x^3 + (35/2)x^2 - (61/12)x - 1/3

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Q. What is the constant term in the expression

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(1)/(12)(x-4)-(5)/(2)x(x^{2}-7x+1)

Distribute and Combine Terms: Simplify the expression by distributing and combining like terms. $\newline$ $(\frac{1}{12})(x-4) - (\frac{5}{2})x(x^2 - 7x + 1)$ $\newline$ = $(\frac{1}{12})x - (\frac{1}{3}) - (\frac{5}{2})x^3 + (\frac{35}{2})x^2 - (\frac{5}{2})x$
Combine Like Terms: Combine like terms to simplify further. $\newline$ Combine the $x$ terms and constant terms separately. $\newline$ $= -\left(\frac{5}{2}\right)x^3 + \left(\frac{35}{2}\right)x^2 + \left(\left(\frac{1}{12}\right) - \left(\frac{5}{2}\right) - \left(\frac{1}{3}\right)\right)x - \frac{1}{3}$ $\newline$ $= -\left(\frac{5}{2}\right)x^3 + \left(\frac{35}{2}\right)x^2 - \left(\frac{61}{12}\right)x - \frac{1}{3}$