Identify integral: Identify the integral to be solved.We need to evaluate the integral of the function −2xe2x with respect to x.I=∫−2xe2xdx
Use integration by parts: Use integration by parts.Integration by parts formula is ∫udv=uv−∫vdu, where u and dv are parts of the integrand.Let u=−2x (which will be differentiated) and dv=e2xdx (which will be integrated).
Differentiate and integrate: Differentiate u and integrate dv. Differentiating u with respect to x gives us du=−2dx. Integrating dv with respect to x gives us v=21e2x, since the integral of eax is a1eax and here dv0.
Apply integration by parts: Apply the integration by parts formula.Now we have u=−2x, du=−2dx, v=21e2x.Using the integration by parts formula, we get:I=uv−∫vduI=(−2x)(21)e2x−∫(21)e2x(−2dx)
Simplify expression: Simplify the expression.I=−xe2x−∫−e2xdxNow we need to integrate −e2x with respect to x.
Integrate −e2x: Integrate −e2x with respect to x. The integral of −e2x is −21e2x, since the integral of eax is a1eax and here a=2.
Combine and add constant: Combine the results and add the constant of integration.I=−xe2x−(−21)e2x+CI=−xe2x+(21)e2x+C
Write final answer: Write the final answer.The integral of −2xe2x with respect to x is:I=−xe2x+(21)e2x+C
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