What could be the value of x in the following equation? Select all that apply. x^2 = 1/36 Multi-select Choices: (A)1/18 (B)sqrt 1/36 (C)-1/18 (D)-sqrt 1/36

Solve for x: Step 1: Solve for x by taking the square root of both sides. x = ±sqrt(1/36) Calculation: sqrt(1/36) = 1/6 So, x = ±1/6 Check possible values: Step 2: Check the possible values of x against the multi-select choices. x = 1/6 matches (A)1/18? No x = 1/6 matches (B)sqrt 1/36? No x = 1/6 matches (C)-1/18? No x = 1/6 matches (D)-sqrt 1/36? No x = -1/6 matches (A)1/18? No x = -1/6 matches (B)sqrt 1/36? No x = -1/6 matches (C)-1/18? Yes x = -1/6 matches (D)-sqrt 1/36? No

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What could be the value of $x$ in the following equation? Select all that apply. $\newline$ $x^2 = \frac{1}{36}$ $\newline$ Multi-select Choices: $\newline$ (A) $\frac{1}{18}$ $\newline$ (B) $\sqrt{\frac{1}{36}}$ $\newline$ (C) $-\frac{1}{18}$ $\newline$ (D) $-\sqrt{\frac{1}{36}}$

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Math Problems

Calculus

Find indefinite integrals using the substitution

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Q. What could be the value of

x

in the following equation? Select all that apply.

\newline

x^2 = \frac{1}{36}

\newline

Multi-select Choices:

\newline

(A)

\frac{1}{18}

\newline

(B)

\sqrt{\frac{1}{36}}

\newline

(C)

-\frac{1}{18}

\newline

(D)

-\sqrt{\frac{1}{36}}

Solve for x: Step $1$ : Solve for x by taking the square root of both sides. $\newline$ $x = \pm\sqrt{\frac{1}{36}}$ $\newline$ Calculation: $\sqrt{\frac{1}{36}} = \frac{1}{6}$ $\newline$ So, $x = \pm\frac{1}{6}$
Check possible values: Step $2$ : Check the possible values of $x$ against the multi-select choices. $\newline$ $x = \frac{1}{6}$ matches (A) $\frac{1}{18}$ ? No $\newline$ $x = \frac{1}{6}$ matches (B) $\sqrt{\frac{1}{36}}$ ? No $\newline$ $x = \frac{1}{6}$ matches (C) $-\frac{1}{18}$ ? No $\newline$ $x = \frac{1}{6}$ matches (D) $-\sqrt{\frac{1}{36}}$ ? No $\newline$ $x = -\frac{1}{6}$ matches (A) $\frac{1}{18}$ ? No $\newline$ $x = -\frac{1}{6}$ matches (B) $\sqrt{\frac{1}{36}}$ ? No $\newline$ $x = -\frac{1}{6}$ matches (C) $-\frac{1}{18}$ ? Yes $\newline$ $x = -\frac{1}{6}$ matches (D) $-\sqrt{\frac{1}{36}}$ ? No