Simplify Integrand: Simplify the integrand by dividing each term in the numerator by each term in the denominator.We have the integral:∫x2+2x3+xdxWe can split this into two separate integrals:∫x2+2x3dx + ∫x2+2xdx
Split into Two Integrals: Simplify the first integral by recognizing that the numerator is the derivative of the denominator.For the first integral, we have:∫x2+2x3dxLet u=x2+2, then du=2xdx, which means xdx=2du.Substitute u and du into the integral:21∫uu−2du
Substitute and Integrate: Simplify the second integral by recognizing it as a standard form.For the second integral, we have:∫x2+2xdxThis is a standard form that can be integrated directly.Let's integrate it:21ln∣x2+2∣+C
Integrate First Integral: Integrate the first integral after substitution.We have:21∫(uu−2)duSplit the integral:21(∫1du−2∫u1du)Integrate term by term:21(u−2ln∣u∣)+C
Substitute Back: Substitute back the original variable x into the first integral.We have:21∗(u−2ln∣u∣)+CSubstitute back u=x2+2:21∗((x2+2)−2ln∣x2+2∣)+C
Combine Final Answer: Combine the results from Step 3 and Step 5 to get the final answer.We have:21×((x2+2)−2ln∣x2+2∣)+21×ln∣x2+2∣+CSimplify the expression:21×x2+1−ln∣x2+2∣+C
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