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Solve the equation using the multiplication property of equality: \newline215=y5\frac{2}{15} = -\frac{y}{5}\newlineThe solution set is __________.

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Q. Solve the equation using the multiplication property of equality: \newline215=y5\frac{2}{15} = -\frac{y}{5}\newlineThe solution set is __________.
  1. Use multiplication property of equality: We are given the equation (215)=(y5)(\frac{2}{15}) = -(\frac{y}{5}). To find the value of yy, we will use the multiplication property of equality, which states that we can multiply both sides of an equation by the same non-zero number without changing the equality.
  2. Multiply by 55: Multiply both sides of the equation by 55 to eliminate the denominator on the right side of the equation.\newline5×215=5×(y5)5 \times \frac{2}{15} = 5 \times -\left(\frac{y}{5}\right)
  3. Perform multiplication: Perform the multiplication on both sides.\newline(5×2)/15=y(5 \times 2) / 15 = -y
  4. Simplify left side: Simplify the left side of the equation. 1015=y\frac{10}{15} = -y
  5. Reduce fraction: Reduce the fraction 1015\frac{10}{15} to its simplest form.\newline23=y\frac{2}{3} = -y
  6. Get rid of negative sign: To solve for yy, we need to get rid of the negative sign. We can multiply both sides by 1-1.1×(23)=1×y-1 \times \left(\frac{2}{3}\right) = -1 \times -y
  7. Final solution: Perform the multiplication on both sides.\newline23=y-\frac{2}{3} = y