Q. Find the truth set of the following simultaneous equation65x−43y=21×32y=25
Simplify Equations: Simplify the equations:First equation: (65x−43y=21)Second equation: (32y=25)
Solve for y: Solve the second equation for y:32y=25Multiply both sides by 23 to isolate y:y=(25)×(23)=415
Substitute y into First Equation: Substitute y=415 into the first equation:65x−43×415=2165x−1645=21
Solve for x: Solve for x:First, convert 21 to a fraction with a denominator of 16:21=168Now, add 1645 to both sides:65x=168+164565x=1653Multiply both sides by 56 to solve for x:x=1653⋅56=80318Simplify x:x=40159
More problems from Find indefinite integrals using the substitution