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Let 
f be the function defined by 
f(x)=4sqrtx. If three subintervals of equal length are used, what is the value of the right Riemann sum approximation for 
int_(0)^(9)4sqrtxdx ? Round to the nearest thousandth if necessary.
Answer:

Let f f be the function defined by f(x)=4x f(x)=4 \sqrt{x} . If three subintervals of equal length are used, what is the value of the right Riemann sum approximation for 094xdx \int_{0}^{9} 4 \sqrt{x} d x ? Round to the nearest thousandth if necessary.\newlineAnswer:

Full solution

Q. Let f f be the function defined by f(x)=4x f(x)=4 \sqrt{x} . If three subintervals of equal length are used, what is the value of the right Riemann sum approximation for 094xdx \int_{0}^{9} 4 \sqrt{x} d x ? Round to the nearest thousandth if necessary.\newlineAnswer:
  1. Determine Subinterval Length: To approximate the integral of f(x)=4xf(x) = 4\sqrt{x} from 00 to 99 using a right Riemann sum with three subintervals of equal length, we first need to determine the length of each subinterval. The interval [0,9][0, 9] is divided into three equal parts, so each subinterval has a length of 93=3\frac{9}{3} = 3.
  2. Find Right Endpoints: Next, we need to find the right endpoints of each subinterval. Since we are using a right Riemann sum, we will evaluate the function at these right endpoints. The right endpoints are x=3x = 3, x=6x = 6, and x=9x = 9.
  3. Evaluate Function at Endpoints: Now we evaluate the function f(x)=4xf(x) = 4\sqrt{x} at each of the right endpoints. This gives us f(3)=43f(3) = 4\sqrt{3}, f(6)=46f(6) = 4\sqrt{6}, and f(9)=49f(9) = 4\sqrt{9}.
  4. Calculate Function Values: We calculate the values: f(3)=434×1.732=6.928f(3) = 4\sqrt{3} \approx 4 \times 1.732 = 6.928, f(6)=464×2.449=9.796f(6) = 4\sqrt{6} \approx 4 \times 2.449 = 9.796, and f(9)=49=4×3=12f(9) = 4\sqrt{9} = 4 \times 3 = 12.
  5. Calculate Riemann Sum: The right Riemann sum is the sum of the products of the function values at the right endpoints and the length of each subinterval. So, the right Riemann sum RR is R=(f(3)+f(6)+f(9))×length of subinterval.R = (f(3) + f(6) + f(9)) \times \text{length of subinterval}.
  6. Substitute Values: Substitute the values we found into the Riemann sum formula: R=(6.928+9.796+12)×3R = (6.928 + 9.796 + 12) \times 3.
  7. Perform Calculation: Perform the calculation: R=(6.928+9.796+12)×328.724×386.172R = (6.928 + 9.796 + 12) \times 3 \approx 28.724 \times 3 \approx 86.172.
  8. Round Result: Round the result to the nearest thousandth: R86.172R \approx 86.172.