Let E = {2, 6} and F = {1, 3, 4, 5, 7}. What is E ∩ F? Choices: (A) ∅ (B){1, 2, 3, 4, 5, 6, 7} (C){1, 2, 5, 6} (D){1, 2, 5, 6, 7}

Define Sets E and F: E = {2, 6} and F = {1, 3, 4, 5, 7} are given. To find the intersection E ∩ F, we need to find the elements that are common to both sets E and F.Find Common Elements: We compare each element of set E with each element of set F to determine if there are any common elements.Check Element 2: The element 2 from set E is not present in set F, which contains {1, 3, 4, 5, 7}.Check Element 6: The element 6 from set E is also not present in set F, which contains {1, 3, 4, 5, 7}.Identify Intersection: Since there are no common elements between set E and set F, the intersection E ∩ F is the empty set, denoted by ∅.

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Let $E = \{2, 6\}$ and $F = \{1, 3, 4, 5, 7\}$ . What is $E \cap F$ ? $\newline$ Choices: $\newline$ (A) $\emptyset$ $\newline$ (B) $\{1, 2, 3, 4, 5, 6, 7\}$ $\newline$ (C) $\{1, 2, 5, 6\}$ $\newline$ (D) $\{1, 2, 5, 6, 7\}$

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Q. Let

E = \{2, 6\}

and

F = \{1, 3, 4, 5, 7\}

. What is

E \cap F

\newline

Choices:

\newline

(A)

\emptyset

\newline

(B)

\{1, 2, 3, 4, 5, 6, 7\}

\newline

(C)

\{1, 2, 5, 6\}

\newline

(D)

\{1, 2, 5, 6, 7\}

Define Sets $E$ and $F$ : $E = \{2, 6\}$ and $F = \{1, 3, 4, 5, 7\}$ are given. To find the intersection $E \cap F$ , we need to find the elements that are common to both sets $E$ and $F$ .
Find Common Elements: We compare each element of set $E$ with each element of set $F$ to determine if there are any common elements.
Check Element $2$ : The element $2$ from set $E$ is not present in set $F$ , which contains \{$$1$, $3$, $4$, $5$, $7$\}.
Check Element $6$: The element $6$ from set $E$ is also not present in set $F$, which contains \{$1, 3, 4, 5, 7$\}.
Identify Intersection: Since there are no common elements between set $E$ and set $F$, the intersection $E \cap F$ is the empty set, denoted by $\emptyset$.