Let D = {8, 14} and E = {0, 4, 18}. What is D ∩ E? Choices: (A){0} (B){0, 4, 8, 14, 18} (C){0, 4, 8, 18} (D) ∅

Define Sets D and E: Define the sets D and E. D = {8, 14} E = {0, 4, 18} The intersection of two sets is the set of elements that are common to both sets.Find Intersection of D and E: Find the intersection of sets D and E. To find D ∩ E, we look for elements that are present in both set D and set E. D ∩ E = {elements that are in both D and E}Compare Elements of D and E: Compare the elements of set D with the elements of set E. We see that: - 8 is in D but not in E. - 14 is in D but not in E. - 0 is in E but not in D. - 4 is in E but not in D. - 18 is in E but not in D. Therefore, there are no elements that are common to both sets D and E.Conclude Intersection of D and E: Conclude the intersection of sets D and E. Since there are no common elements between set D and set E, the intersection of D and E is the empty set. D ∩ E = ∅

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Let $D = \{8, 14\}$ and $E = \{0, 4, 18\}$ . What is $D \cap E$ ? $\newline$ Choices: $\newline$ (A) $\{0\}$ $\newline$ (B) $\{0, 4, 8, 14, 18\}$ $\newline$ (C) $\{0, 4, 8, 18\}$ $\newline$ (D) $\emptyset$

View step-by-step help

Full solution

Q. Let

D = \{8, 14\}

and

E = \{0, 4, 18\}

. What is

D \cap E

\newline

Choices:

\newline

(A)

\{0\}

\newline

(B)

\{0, 4, 8, 14, 18\}

\newline

(C)

\{0, 4, 8, 18\}

\newline

(D)

\emptyset

Define Sets D and E: Define the sets D and E. $\newline$ $D = \{8, 14\}$ $\newline$ $E = \{0, 4, 18\}$ $\newline$ The intersection of two sets is the set of elements that are common to both sets.
Find Intersection of D and E: Find the intersection of sets $D$ and $E$ . To find $D \cap E$ , we look for elements that are present in both set $D$ and set $E$ . $D \cap E = \{\text{elements that are in both } D \text{ and } E\}$
Compare Elements of D and E: Compare the elements of set $D$ with the elements of set $E$ . We see that: - $8$ is in $D$ but not in $E$ . - $14$ is in $D$ but not in $E$ . - $0$ is in $E$ but not in $D$ . - $E$ $1$ is in $E$ but not in $D$ . - $E$ $4$ is in $E$ but not in $D$ . Therefore, there are no elements that are common to both sets $D$ and $E$ .
Conclude Intersection of D and E: Conclude the intersection of sets $D$ and $E$ . Since there are no common elements between set $D$ and set $E$ , the intersection of $D$ and $E$ is the empty set. $D \cap E = \emptyset$