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∫
3
x
−
2
d
x
\int 3x^{-2}\,dx
∫
3
x
−
2
d
x
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Math Problems
Calculus
Find indefinite integrals using the substitution and by parts
Full solution
Q.
∫
3
x
−
2
d
x
\int 3x^{-2}\,dx
∫
3
x
−
2
d
x
Write Integral:
Write down the integral to be solved.
\newline
I
=
∫
3
x
−
2
d
x
I = \int 3x^{-2}\,dx
I
=
∫
3
x
−
2
d
x
Simplify Integral:
Simplify the integral.
I
=
3
∫
x
−
2
d
x
I = 3\int x^{-2}\,dx
I
=
3
∫
x
−
2
d
x
Recall Power Rule:
Recall the power rule for integration,
∫
x
n
d
x
=
x
n
+
1
n
+
1
+
C
\int x^n \, dx = \frac{x^{n+1}}{n+1} + C
∫
x
n
d
x
=
n
+
1
x
n
+
1
+
C
, where
n
≠
−
1
n \neq -1
n
=
−
1
.
Apply Power Rule:
Apply the power rule to the integral.
\newline
I
=
3
(
x
(
−
2
+
1
)
(
−
2
+
1
)
)
+
C
I = 3\left(\frac{x^{(-2+1)}}{(-2+1)}\right) + C
I
=
3
(
(
−
2
+
1
)
x
(
−
2
+
1
)
)
+
C
\newline
I
=
3
(
x
(
−
1
)
(
−
1
)
)
+
C
I = 3\left(\frac{x^{(-1)}}{(-1)}\right) + C
I
=
3
(
(
−
1
)
x
(
−
1
)
)
+
C
Simplify Expression:
Simplify the expression.
\newline
I
=
−
3
x
−
1
+
C
I = -3x^{-1} + C
I
=
−
3
x
−
1
+
C
\newline
I
=
−
3
x
+
C
I = -\frac{3}{x} + C
I
=
−
x
3
+
C
Final Answer:
Write the final answer.
\newline
The indefinite integral of
3
x
−
2
3x^{-2}
3
x
−
2
with respect to
x
x
x
is
−
3
x
+
C
-\frac{3}{x} + C
−
x
3
+
C
.
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\newline
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