Given Integral: We are given the integral: ∫(x2−2x+5)2x3−2x2+1dxTo solve this integral, we will use the method of partial fractions. However, the denominator (x2−2x+5)2 does not factor into linear terms over the real numbers because the discriminant 22−4⋅1⋅5 is negative. Therefore, we cannot decompose the fraction into simpler partial fractions directly. Instead, we will complete the square for the denominator and then try to simplify the integral.
Complete the Square: First, let's complete the square for the denominator:x2−2x+5=(x2−2x+1)+4=(x−1)2+4Now, the integral becomes:∫((x−1)2+4)2(x3−2x2+1)dx
Substitution: Next, we will make a substitution to simplify the integral. Let: u=x−1 Then, du=dx, and x=u+1 Now we can rewrite the integral in terms of u: ∫((u+1)3−2(u+1)2+1)du/(u2+4)2
Expand and Simplify: We expand the numerator to simplify the expression:∫(u2+4)2(u3+3u2+3u+1)−2(u2+2u+1)+1du= ∫(u2+4)2(u3+3u2+3u+1−2u2−4u−2+1)du= ∫(u2+4)2(u3+u2−u)du
Split into Integrals: Now, we will split the integral into three separate integrals: ∫(u2+4)2u3du + ∫(u2+4)2u2du - ∫(u2+4)2udu
Complex Integral: The first integral ∫(u3du)/(u2+4)2 is a bit complex and does not have a straightforward antiderivative. We will need to use a method such as integration by parts or a further substitution. However, this is a non-standard integral and may require a special function or a numerical method to solve. At this point, we realize that the approach we have taken may not be the most efficient, and we may need to reconsider our strategy.
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